Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
Discussion:
123 comments Page 2 of 13.
Noblen said:
4 years ago
50.10 is the correct answer.
It is not a triangle so don't use similar triangles. it is a logarithmic function. interpolate it using ln.
It is not a triangle so don't use similar triangles. it is a logarithmic function. interpolate it using ln.
(4)
Niva said:
5 years ago
Liquid limit-water content by soil with small shear strength.
(3)
Aakash Karoo said:
1 decade ago
STEP 1: Just draw the rough graph on which, no. of blows on X-axis and moisture content on Y-axis.
STEP 2: Join the coordinates A (20, 70) and B (100, 20).
STEP 3 : Draw the vertical line from 25 no. of blows to the line AB and mark it.
STEP 4 : Draw horizontal line from the marked point on line AB to the point on Y-axis, that same will give us the liquid limit of soil sample (i.e. 65%).
OR,
Liquid Limit = Wl1 = W1*(N2/25)^0.121.
Wl2 = W2*(N1/25)^0.121.
Where,
W = Water content at N blows.
N = No. of blows.
Liquid limit = 70*(100/25)^0.121 = 82.78%.
Liquid Limit = 20*(10/25)^0.121 = 17.90%.
Required liquid limit = 82.78-17.90 = 64.87%.
= 65.00%.
STEP 2: Join the coordinates A (20, 70) and B (100, 20).
STEP 3 : Draw the vertical line from 25 no. of blows to the line AB and mark it.
STEP 4 : Draw horizontal line from the marked point on line AB to the point on Y-axis, that same will give us the liquid limit of soil sample (i.e. 65%).
OR,
Liquid Limit = Wl1 = W1*(N2/25)^0.121.
Wl2 = W2*(N1/25)^0.121.
Where,
W = Water content at N blows.
N = No. of blows.
Liquid limit = 70*(100/25)^0.121 = 82.78%.
Liquid Limit = 20*(10/25)^0.121 = 17.90%.
Required liquid limit = 82.78-17.90 = 64.87%.
= 65.00%.
(2)
Pintu kumar(Govt.poly saharsa,bihar said:
6 years ago
Given,
n1=10, w1=70%.
n2=100, w2=20%.
liquid limit(1) = 70*(100÷25)^.121 = 82.78.
liquid limit(2) = 20*(10÷25)^.121 = 17.90.
Total = (82.78-17.90) = 65%.
Ans 65%.
n1=10, w1=70%.
n2=100, w2=20%.
liquid limit(1) = 70*(100÷25)^.121 = 82.78.
liquid limit(2) = 20*(10÷25)^.121 = 17.90.
Total = (82.78-17.90) = 65%.
Ans 65%.
(2)
ASHISH WAGHMARE said:
1 decade ago
STEP1: just draw the rough graph on which, no. of blows on X-axis and moisture content on Y-axis.
80%.
M C 70%. .A(10,70%)
O O 60%.
I N 50%.
S T 40%.
T E 30%.
U N 20%. .B(100,20%)
R T 10%.
E(%)0% . . . . . . . . . . . .
0 10 20 30 40 50 60 70 80 90 100 110
NO. OF BLOWS
STEP2: Join the coordinates A and B.
STEP3: draw the vertical line from 25 no. of blows to the line AB and mark it.
STEP4: Draw horizontal line from the marked point on line AB To the pt. on Y-axis, that same will give us the liquid limit of soil sample(ie. 65%).
(NOTE: ALL STEPS ARE TAKEN FROM EXPERIMENT OF DETERMINATION OF LIQUID LIMIT BY USING LIQUID LIMIT DEVICE)
80%.
M C 70%. .A(10,70%)
O O 60%.
I N 50%.
S T 40%.
T E 30%.
U N 20%. .B(100,20%)
R T 10%.
E(%)0% . . . . . . . . . . . .
0 10 20 30 40 50 60 70 80 90 100 110
NO. OF BLOWS
STEP2: Join the coordinates A and B.
STEP3: draw the vertical line from 25 no. of blows to the line AB and mark it.
STEP4: Draw horizontal line from the marked point on line AB To the pt. on Y-axis, that same will give us the liquid limit of soil sample(ie. 65%).
(NOTE: ALL STEPS ARE TAKEN FROM EXPERIMENT OF DETERMINATION OF LIQUID LIMIT BY USING LIQUID LIMIT DEVICE)
(1)
Sukriti dan said:
9 years ago
As per flow index method I get 50.10. By the interpolation I get 61.6. But LIQUID LIMIT = Wn (N / 25)^n, I get 65.
(1)
Abdul Quader said:
6 years ago
N1=10, W1=70% & N2=100, W2=20%.
WL1 = W1*(N1/25)^0.121 = 70*(10/25)^0.121 = 62.65%,
WL2 = W2*(N2/25)^0.121 = 20*(100/25)^0.121 = 23.65,
Required Liquid Limit= WL1 - WL2.
= 62.65 - 23.65,
= 39%.
So, Answer (D) None of These.
WL1 = W1*(N1/25)^0.121 = 70*(10/25)^0.121 = 62.65%,
WL2 = W2*(N2/25)^0.121 = 20*(100/25)^0.121 = 23.65,
Required Liquid Limit= WL1 - WL2.
= 62.65 - 23.65,
= 39%.
So, Answer (D) None of These.
(1)
Hardik said:
6 years ago
How to find 4^0.12 without a calculator?
(1)
Ashirwad said:
1 decade ago
Liquid limit is defined as the moisture content at which a groove made in a pat of soil will flow through a distance of 13mm under an impact of 25 blows. Using linear interpolation with the help of flow curve we can get the above.
Pratima Yadav said:
1 decade ago
Liquid Limit= W * (N/25)^0.121.
where,
W= water content at N blows.
N= no.of blows.
where,
W= water content at N blows.
N= no.of blows.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers