Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 19)
19.
A soil sample has passing 0.075 mm sieve = 60% liquid limit = 65% and plastic limit = 40%. The group index of the soil, is
5
20
40
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
48 comments Page 3 of 5.

Danish murtaza zaidi said:   7 years ago
a = P - 35 = 60 - 35 = 25.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 40 - 10 = 30.

Now,
GI= 0.2a+0.005ac+0.01bd.
Thus,
GI= 0.2(25)+0.005(25)(25)+0.01(45)(30),
GI= 5+3.125+13.5,
GI= 21.625 ~ 22,
Option D is the answer.

Prakash said:   7 years ago
@Danish Murtaza Zaidi.

You are almost correct.

In the Ip {plasticity index} greater than 10% and not more than 30% ie. Range should be 1 to 20.

It means d=15-10=5.
And hence the answer is 10.125.

Chandan sen said:   7 years ago
a=60-35=25,
b=60-15=45 not more then 40 so,
b=40,
c=65-40=25,
d=(65-40)-10=15,
GI=0.2*25+0.01*40*15+0.005*25*25=14.125.

Somer said:   7 years ago
If soil passing in 75micron is 15%, plasticity index is 6%, not mentioned the liquid limit, then what is the group index of soil?

Naresh said:   7 years ago
No @All.

The group index should be rounded to nearest whole number suppose GI = 14.125 it should be rounded off to 14.

Suprava said:   7 years ago
The Ans will be 13.5.

Jeremiah said:   7 years ago
The correct answer is 13.5.

Gui said:   7 years ago
Yes, the correct Answer 13.5.

Amit naik said:   6 years ago
The correct answer is option D. Agree with the given answer.

MN Yogi said:   6 years ago
GI = .2a +.005ac +.01bd.

a = 25,
b = 45, bt not more than 40, = 40,
c = 25, bt nt more thn 20, = 20,
d = 15,
GI = .2 * 25 +.005 * 25 * 20 +.01 * 40 * 15 = 13.5.


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