Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 19)
19.
A soil sample has passing 0.075 mm sieve = 60% liquid limit = 65% and plastic limit = 40%. The group index of the soil, is
Discussion:
48 comments Page 2 of 5.
Ravi Kant said:
9 years ago
a = 60-35 = 25%
b = 60-15 = 45%
c = 65-40 = 25%
d = PI-10 = (65-40)-10 = 15%.
GI = 0.2a + 0.005ac + 0.01bd = 0.2 * 25 + 0.005 * 25 * 25 + 0.01 * 45 * 15 = 14.875.
b = 60-15 = 45%
c = 65-40 = 25%
d = PI-10 = (65-40)-10 = 15%.
GI = 0.2a + 0.005ac + 0.01bd = 0.2 * 25 + 0.005 * 25 * 25 + 0.01 * 45 * 15 = 14.875.
CHAUDHARY said:
8 years ago
@Samkit
GI = .2 * 25 + .01 * 40 * 15 + .005 * 20 * 25 = 13.5.
GI = .2 * 25 + .01 * 40 * 15 + .005 * 20 * 25 = 13.5.
Pinkesh said:
8 years ago
GI = . 2a +. 005ac +. 01bd.
a = 25,
b = 45, bt not more than 40, = 40,
c = 25, bt nt more thn 20, = 20,
d = 15,
GI = . 2*25 +. 005*25*20 +. 01*40*15 = 13.5.
a = 25,
b = 45, bt not more than 40, = 40,
c = 25, bt nt more thn 20, = 20,
d = 15,
GI = . 2*25 +. 005*25*20 +. 01*40*15 = 13.5.
Akash D Sajjanar said:
8 years ago
GI= 0.2a+0.005ac+0.01bd.
a= % passing 0.075 mm sieve (min 35 max 75)= 60-35= 25 (max value is 40 if >40 take a value as 40).
b= % passing 0.075 mm sieve (min 15 max 55)= 60-15= 45 > 40 so take b=40.
c= liquid limit max 40 = 65-40 = 25 > 20 so take c=20.
d= plasticity index = 25-10 = 15 < 20 so d=15.
GI = (0.2*25)+(0.005*25*25)+(.01*40*15)=14.125.
So, answer is GI=14.125.
a= % passing 0.075 mm sieve (min 35 max 75)= 60-35= 25 (max value is 40 if >40 take a value as 40).
b= % passing 0.075 mm sieve (min 15 max 55)= 60-15= 45 > 40 so take b=40.
c= liquid limit max 40 = 65-40 = 25 > 20 so take c=20.
d= plasticity index = 25-10 = 15 < 20 so d=15.
GI = (0.2*25)+(0.005*25*25)+(.01*40*15)=14.125.
So, answer is GI=14.125.
Praful sl said:
8 years ago
Not 14.875, 14.125 is correct.
Ganesh sharma said:
8 years ago
Answer will be 13.5.
Kamlesh said:
8 years ago
16.125 is the correct and,
a = 25.
b = 40.
c = 25.
d = 20.
a = 25.
b = 40.
c = 25.
d = 20.
Parteek said:
8 years ago
PI in the formula is Plasticity Index= LL-PL not Plastic limit which some person are taking in above answers.
Debasmita said:
8 years ago
14.875 is the answer.
Inte said:
7 years ago
a= p-35 = 60-35=25<40 so ok
b= p- 15=60-15=45>40 so take b=40
c= LL-40=65-40=25>20 so take c=20
d=plasticity index - 10=(65-40)-10=15<20 so ok
G. I.= 0.2a+0.005ac+0.01bd.
G. I.=0.2*25+0.005*25*20+0.01*40*15.
G.I. = 13.5.
b= p- 15=60-15=45>40 so take b=40
c= LL-40=65-40=25>20 so take c=20
d=plasticity index - 10=(65-40)-10=15<20 so ok
G. I.= 0.2a+0.005ac+0.01bd.
G. I.=0.2*25+0.005*25*20+0.01*40*15.
G.I. = 13.5.
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