Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 19)
19.
A soil sample has passing 0.075 mm sieve = 60% liquid limit = 65% and plastic limit = 40%. The group index of the soil, is
Discussion:
48 comments Page 3 of 5.
Gui said:
7 years ago
Yes, the correct Answer 13.5.
Jeremiah said:
7 years ago
The correct answer is 13.5.
Suprava said:
7 years ago
The Ans will be 13.5.
Naresh said:
7 years ago
No @All.
The group index should be rounded to nearest whole number suppose GI = 14.125 it should be rounded off to 14.
The group index should be rounded to nearest whole number suppose GI = 14.125 it should be rounded off to 14.
Somer said:
7 years ago
If soil passing in 75micron is 15%, plasticity index is 6%, not mentioned the liquid limit, then what is the group index of soil?
Chandan sen said:
7 years ago
a=60-35=25,
b=60-15=45 not more then 40 so,
b=40,
c=65-40=25,
d=(65-40)-10=15,
GI=0.2*25+0.01*40*15+0.005*25*25=14.125.
b=60-15=45 not more then 40 so,
b=40,
c=65-40=25,
d=(65-40)-10=15,
GI=0.2*25+0.01*40*15+0.005*25*25=14.125.
Prakash said:
7 years ago
@Danish Murtaza Zaidi.
You are almost correct.
In the Ip {plasticity index} greater than 10% and not more than 30% ie. Range should be 1 to 20.
It means d=15-10=5.
And hence the answer is 10.125.
You are almost correct.
In the Ip {plasticity index} greater than 10% and not more than 30% ie. Range should be 1 to 20.
It means d=15-10=5.
And hence the answer is 10.125.
Danish murtaza zaidi said:
7 years ago
a = P - 35 = 60 - 35 = 25.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 40 - 10 = 30.
Now,
GI= 0.2a+0.005ac+0.01bd.
Thus,
GI= 0.2(25)+0.005(25)(25)+0.01(45)(30),
GI= 5+3.125+13.5,
GI= 21.625 ~ 22,
Option D is the answer.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 40 - 10 = 30.
Now,
GI= 0.2a+0.005ac+0.01bd.
Thus,
GI= 0.2(25)+0.005(25)(25)+0.01(45)(30),
GI= 5+3.125+13.5,
GI= 21.625 ~ 22,
Option D is the answer.
Inte said:
7 years ago
a= p-35 = 60-35=25<40 so ok
b= p- 15=60-15=45>40 so take b=40
c= LL-40=65-40=25>20 so take c=20
d=plasticity index - 10=(65-40)-10=15<20 so ok
G. I.= 0.2a+0.005ac+0.01bd.
G. I.=0.2*25+0.005*25*20+0.01*40*15.
G.I. = 13.5.
b= p- 15=60-15=45>40 so take b=40
c= LL-40=65-40=25>20 so take c=20
d=plasticity index - 10=(65-40)-10=15<20 so ok
G. I.= 0.2a+0.005ac+0.01bd.
G. I.=0.2*25+0.005*25*20+0.01*40*15.
G.I. = 13.5.
Debasmita said:
8 years ago
14.875 is the answer.
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