Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

The answer will be 14.875..so, The option none of these is the correct one.

GI= 0.2a+0.005ac+0.01bd.
a= % of soil passing through 0.075 sieve - 35.
b= % of soil passing through 0.075 sieve - 15.
c= Liquid limit - 40,
d= plasticity index - 10,
Plasticity index= Liquid limit - Plastic limit.

I think b value is zero as b is the percentage of soil passing through 0.074 mm sieve in excess of 15%, not exceeding 55%. But given here as 60% which is greater than 55%. So, I think b=0.

Correct @Pritam Yadav.

a & b should not be greater than 40.
c & d should not be greater than 20.

Given:- % passing (P) =60%, LL = 65%, PL = 40%.

We have GI = 0.2a+0.005ac+0.01bd.

To get a,b,c and d value, we need Percentage passing 75 micron IS sieve, Liquid Limit and Plasticity Index.

So Plasticity index = LL - PL = 65-40= 25.
Now a= 60-35=25 (value is 0-40),
b =60-15 =45 (value >40, so take 40),
c= 65-40=25 (value > 20, so take 20),
d = 25-10=15 (value between 0 to 20),
Now GI= 0.2 x 25 + 0.005 x 25 x 20 + 0.01 x 40 x 15 = 13.5.

So the answer is D.

13.5 is correct answer.

a = (60-35) = 25
b = (60-15) = 45 is not more than 40 so let b = 40.
c = (65-40) = 25 is not more than 20 so let c = 20.
d= (60-15) = 45 is not more than 40 so let d = 40.

Calc.,
G.I = (0.2x25)+(0.005x25x20)+(0.01x40x20)
= 15.5.

15.5 will be the correct answer.

13.5 will be the correct answer.

13.5 is the correct answer of this question.

GI = .2a +.005ac +.01bd.

a = 25,
b = 45, bt not more than 40, = 40,
c = 25, bt nt more thn 20, = 20,
d = 15,
GI = .2 * 25 +.005 * 25 * 20 +.01 * 40 * 15 = 13.5.

The correct answer is option D. Agree with the given answer.