Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 40)

Soil Mechanics and Foundation Engineering

40.

The angle between the directions of the failure and the major principal plane, is equal to

90° + effective angle of shearing resistance

90° + half of the angle of shearing resistance

45° - half of the angle of shearing resistance

45° + half of the angle of shearing resistance.

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

13 comments Page 1 of 2.

Vivek said: 6 years ago

45 -Φ/2 for active earth pressure.

While 45+Φ/2 for passive earth pressure.

(2)

Subhash said: 5 years ago

Yes, The Correct answer is D. You can check by drawing Mohr circle with coulomb failure envelope.

(1)

Ankitha shetty said: 10 years ago

I think answer C. Anybody want comment? Please.

Vaibhav said: 9 years ago

I agree with you @Ankitha.

Option C is the correct answer.

Umair khan said: 9 years ago

No, the given option D is the right answer.

Vijay said: 9 years ago

Yeah, I agree in option D.

Doyel said: 8 years ago

Can anyone please explain?

Deepak said: 7 years ago

Option C is right. D will be right for minor principal plane.

Narendra modi said: 6 years ago

You are correct, Thanks @Vivek.

Naveen CEG said: 6 years ago

D is correct. C will be the minor principal plane.

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