Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 40)
40.
The angle between the directions of the failure and the major principal plane, is equal to
90° + effective angle of shearing resistance
90° + half of the angle of shearing resistance
45° - half of the angle of shearing resistance
45° + half of the angle of shearing resistance.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.

Prabin khatri said:   3 years ago
I agree with this answer, why because here it says major. So the answer is D.

If minor is written instead of major, Option C would be correct.

Lalita said:   3 years ago
C is the correct answer.

Bishal shahi said:   4 years ago
I agree the right answer is C.

Subhash said:   5 years ago
Yes, The Correct answer is D. You can check by drawing Mohr circle with coulomb failure envelope.
(1)

Naveen CEG said:   6 years ago
D is correct. C will be the minor principal plane.

Narendra modi said:   6 years ago
You are correct, Thanks @Vivek.

Vivek said:   6 years ago
45 -Φ/2 for active earth pressure.

While 45+Φ/2 for passive earth pressure.
(2)

Deepak said:   7 years ago
Option C is right. D will be right for minor principal plane.

Doyel said:   8 years ago
Can anyone please explain?

Vijay said:   9 years ago
Yeah, I agree in option D.


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