Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 1)
1.
The maximum shear stress occurs on the filament which makes an angle with the horizontal plane equal to
Discussion:
13 comments Page 1 of 2.
Shah Sawar said:
4 years ago
Shear stress in a soil mass subjected to principal stress,
P1 and P2, = {(P1-P2)/2}*Sin2a.
Where a is the angle of the failure plane with the horizontal.
For "a" = 45, Sin will give max value and hence we will obtain max shear stress.
P1 and P2, = {(P1-P2)/2}*Sin2a.
Where a is the angle of the failure plane with the horizontal.
For "a" = 45, Sin will give max value and hence we will obtain max shear stress.
(2)
Dikshant Nautiyal said:
5 years ago
According to Mohr's circle;
The critical angle is 45+ π by 2.
For cohesion, soil π is zero.
Then the angle between the horizontal plane and shear stress is 45.
The critical angle is 45+ π by 2.
For cohesion, soil π is zero.
Then the angle between the horizontal plane and shear stress is 45.
(1)
Vijay bhargava said:
9 years ago
Can anyone guide me what is meant by filament?
Vijay bhargava said:
9 years ago
Can anyone guide me what is meant by filament?
Amulya Rajbhar said:
9 years ago
@Vijay.
Filament - wedge.
Filament - wedge.
Pramit said:
9 years ago
Here, s = c + σ * tan(φ).
Sandeep redddy said:
9 years ago
s = c+ σ * tan(φ).(φ) = 45degree.
o<tan(φ)<1.
So that angle is 45 degree.
o<tan(φ)<1.
So that angle is 45 degree.
Sumit said:
8 years ago
But tan60 = 1.732.
Sunny said:
7 years ago
Agree @Sumit,
Why not 60°? Give Any explanation.
Why not 60°? Give Any explanation.
Kartick said:
7 years ago
Please anyone elaborate the solution.
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