Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

23. 

For a homogeneous earth dam 50 m high having 2 m free broad, a flow net was constructed and the results were : Number of potential drops = 2.4 Number of flow channels = 0.4. If coefficiency of permeability of the dam mateiral is 3 x 10-3 cm3/sec, the discharge per metre length of dam, is

[A]. 12 x 10-5 m3/sec
[B]. 24 x 10-3 m3/sec
[C]. 6 x 10-5 m3/sec
[D]. 24 x 10-5 m3/sec

Answer: Option D

Explanation:

No answer description available for this question.

Ujwala Prasad said: (Oct 12, 2013)  
q = kh (Nf/Nd) you will get the answer.

Srinivas said: (Dec 23, 2013)  
q = kh(Nf/Nd).

= 3*10^-3*48*(0.4/2.4).

= 24*10^-5.

Rosh said: (Jan 27, 2016)  
K is in cm2/sec not in cm3/sec typing error.

Abhay said: (Feb 3, 2016)  
Discharge Q = kH(Nf/Nd).

Where k = Coefficient of permeability = 3x10^3 cm^2/sec.

H = Ht. of water or head = 50 - 2 = 48 m = 4800 cm.

= 3x10^3*4800*(0.4/2.4).

= 2.4 cm^3/s.

= 24x10 μ m^3/s.

Swathi said: (May 23, 2016)  
The unit of k is cm^2 per second.

Raju Raut said: (Aug 9, 2016)  
We know discharge (Q) = kH x number of flow channel/ number of Drops.

Where k = coeff of permeability and H = water head.

Aliabryne said: (Aug 23, 2016)  
K = 3 * 10^3 cm per sec (convert this to metre) = 3 * 10^5m per sec.

Q = Kh (Nf/Nd) , after putting the values, we get 24 * 10^5.

Chintu said: (Feb 27, 2017)  
Excellent explanation. Thank you all.

Roy said: (Aug 18, 2017)  
As I know the coefficient of permeability's unit is cm/s.

Dhanu said: (Sep 11, 2017)  
Yes, 200 % k value is cm/sec.

Nayan said: (Dec 6, 2017)  
K unit is same as velocity cm/sec.

Mayur said: (Jul 29, 2018)  
Thank you all for explaining this.

Vivek said: (Aug 5, 2018)  
K will be in cm/sec.

It is unit of the coefficient of permeability.

Sushma Thota said: (Aug 15, 2018)  
The discharge PER METER is asked, so the calculated answer must be divided by 100
since 1m=100cm.

So, the given units and given answer are correct.

Jessica said: (Apr 12, 2019)  
Thank you All for explaining.

Keeda said: (Jan 29, 2021)  
Unit of K is cm/sec.

Er Amit Kumar said: (Jan 30, 2021)  
Given data,
K = 3*10^-3cm3/sec
(0.003/100) = 0.00003 m3/sec, OR
3*10^-5m3/sec.

H = (50 -2 ) 48 m.
Nf = .4
Nd = 2.4
Than formula,
Q = kh* (Nf / Nd)

Q = .00003 * 48 * (.4 / 2.4
Q = 0.00024 OR 24*10^-5 m3/sec.

Hadiul Islam said: (Jul 18, 2021)  
Given data,


K = 3*10^-3cm3/sec.
(0.003/100) = 0.00003 m3/sec, OR.
3*10^-5m3/sec.

H = (50 -2 ) 48 m.
Nf = .4,
Nd = 2.4,

Then formula;
Q = kh* (Nf/Nd).

Q = .00003 * 48 * (.4/2.4)
Q = 0.00024 OR 24*10^-5 m3/sec.

Dipak Singh said: (Aug 28, 2021)  
How q=kh (hf/nd)? Please prove it.

Atem Akech Atem said: (Sep 8, 2021)  
How q=k.h/Nd.Nf? Prove it.

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