### Discussion :: Soil Mechanics and Foundation Engineering - Section 2 (Q.No.23)

- Soil Mechanics and Foundation Engineering - Section 1
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Ujwala Prasad said: (Oct 12, 2013) | |

q = kh (Nf/Nd) you will get the answer. |

Srinivas said: (Dec 23, 2013) | |

q = kh(Nf/Nd). = 3*10^-3*48*(0.4/2.4). = 24*10^-5. |

Rosh said: (Jan 27, 2016) | |

K is in cm2/sec not in cm3/sec typing error. |

Abhay said: (Feb 3, 2016) | |

Discharge Q = kH(Nf/Nd). Where k = Coefficient of permeability = 3x10^3 cm^2/sec. H = Ht. of water or head = 50 - 2 = 48 m = 4800 cm. = 3x10^3*4800*(0.4/2.4). = 2.4 cm^3/s. = 24x10 μ m^3/s. |

Swathi said: (May 23, 2016) | |

The unit of k is cm^2 per second. |

Raju Raut said: (Aug 9, 2016) | |

We know discharge (Q) = kH x number of flow channel/ number of Drops. Where k = coeff of permeability and H = water head. |

Aliabryne said: (Aug 23, 2016) | |

K = 3 * 10^3 cm per sec (convert this to metre) = 3 * 10^5m per sec. Q = Kh (Nf/Nd) , after putting the values, we get 24 * 10^5. |

Chintu said: (Feb 27, 2017) | |

Excellent explanation. Thank you all. |

Roy said: (Aug 18, 2017) | |

As I know the coefficient of permeability's unit is cm/s. |

Dhanu said: (Sep 11, 2017) | |

Yes, 200 % k value is cm/sec. |

Nayan said: (Dec 6, 2017) | |

K unit is same as velocity cm/sec. |

Mayur said: (Jul 29, 2018) | |

Thank you all for explaining this. |

Vivek said: (Aug 5, 2018) | |

K will be in cm/sec. It is unit of the coefficient of permeability. |

Sushma Thota said: (Aug 15, 2018) | |

The discharge PER METER is asked, so the calculated answer must be divided by 100 since 1m=100cm. So, the given units and given answer are correct. |

Jessica said: (Apr 12, 2019) | |

Thank you All for explaining. |

Keeda said: (Jan 29, 2021) | |

Unit of K is cm/sec. |

Er Amit Kumar said: (Jan 30, 2021) | |

Given data, K = 3*10^-3cm3/sec (0.003/100) = 0.00003 m3/sec, OR 3*10^-5m3/sec. H = (50 -2 ) 48 m. Nf = .4 Nd = 2.4 Than formula, Q = kh* (Nf / Nd) Q = .00003 * 48 * (.4 / 2.4 Q = 0.00024 OR 24*10^-5 m3/sec. |

Hadiul Islam said: (Jul 18, 2021) | |

Given data, K = 3*10^-3cm3/sec. (0.003/100) = 0.00003 m3/sec, OR. 3*10^-5m3/sec. H = (50 -2 ) 48 m. Nf = .4, Nd = 2.4, Then formula; Q = kh* (Nf/Nd). Q = .00003 * 48 * (.4/2.4) Q = 0.00024 OR 24*10^-5 m3/sec. |

Dipak Singh said: (Aug 28, 2021) | |

How q=kh (hf/nd)? Please prove it. |

Atem Akech Atem said: (Sep 8, 2021) | |

How q=k.h/Nd.Nf? Prove it. |

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