Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 23)
23.
For a homogeneous earth dam 50 m high having 2 m free broad, a flow net was constructed and the results were : Number of potential drops = 2.4 Number of flow channels = 0.4. If coefficiency of permeability of the dam mateiral is 3 x 10-3 cm3/sec, the discharge per metre length of dam, is
Discussion:
22 comments Page 2 of 3.
Mayur said:
7 years ago
Thank you all for explaining this.
Nayan said:
8 years ago
K unit is same as velocity cm/sec.
Dhanu said:
8 years ago
Yes, 200 % k value is cm/sec.
Roy said:
8 years ago
As I know the coefficient of permeability's unit is cm/s.
Chintu said:
8 years ago
Excellent explanation. Thank you all.
Aliabryne said:
9 years ago
K = 3 * 10^3 cm per sec (convert this to metre) = 3 * 10^5m per sec.
Q = Kh (Nf/Nd) , after putting the values, we get 24 * 10^5.
Q = Kh (Nf/Nd) , after putting the values, we get 24 * 10^5.
Raju raut said:
9 years ago
We know discharge (Q) = kH x number of flow channel/ number of Drops.
Where k = coeff of permeability and H = water head.
Where k = coeff of permeability and H = water head.
Swathi said:
9 years ago
The unit of k is cm^2 per second.
Abhay said:
10 years ago
Discharge Q = kH(Nf/Nd).
Where k = Coefficient of permeability = 3x10^3 cm^2/sec.
H = Ht. of water or head = 50 - 2 = 48 m = 4800 cm.
= 3x10^3*4800*(0.4/2.4).
= 2.4 cm^3/s.
= 24x10 μ m^3/s.
Where k = Coefficient of permeability = 3x10^3 cm^2/sec.
H = Ht. of water or head = 50 - 2 = 48 m = 4800 cm.
= 3x10^3*4800*(0.4/2.4).
= 2.4 cm^3/s.
= 24x10 μ m^3/s.
Rosh said:
10 years ago
K is in cm2/sec not in cm3/sec typing error.
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