Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 18)
18.
The fundamental equation of air content (ac), degree of saturation (Sr) and void ratio (e), is
ac = 
ac = 
ac = 
ac = 1 + e/Sr
Discussion:
14 comments Page 1 of 2.
Anees kumar verma said:
7 years ago
Actually here is not air content, here is air voids.
ac+Sr=1, ac=1-Sr.
Na=ac*n, n=e/1+e.
Na=e(1-Sr)/(1+e).
ac+Sr=1, ac=1-Sr.
Na=ac*n, n=e/1+e.
Na=e(1-Sr)/(1+e).
(5)
MAHENDRA KUMAR REDDY said:
8 years ago
Actually, there in place of ac it should be na.
(1)
Vikas said:
8 years ago
You are correct @Souvik.
(1)
Protap said:
7 years ago
@Anees Kumar,
What is Na?
What is Na?
(1)
Biki said:
7 years ago
The percentage of air voids should be on LHS which is equal to porosity*air content, air content is equal to 1-S, porosity = e/1+e.
(1)
Sadananda said:
6 years ago
This is not air content this is % air voids.
(1)
Abhay said:
6 years ago
Air content = 1-degree of saturation.
(1)
Mahender said:
3 years ago
We know that vol Of voids = vol Of air + vol Of water.
Dividing both sides with vol Of voids then we get air content + degree of Saturation = 1.
Dividing both sides with vol Of voids then we get air content + degree of Saturation = 1.
(1)
Swathi said:
9 years ago
It is not air content on the LHS, it is a percentage of air voids.
Yogesh said:
9 years ago
Actually,
ac + sr = 1.
Hence, ac = 1 - sr.
But here, if we resolve the eq in the ans, we will get;
ac = n(1-sr).
Is this valid?
ac + sr = 1.
Hence, ac = 1 - sr.
But here, if we resolve the eq in the ans, we will get;
ac = n(1-sr).
Is this valid?
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