Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 2 (Q.No. 12)
12.
A reinforced concrete cantilever beam is 3.6 m long, 25 cm wide and has its lever arm 40 cm. It carries a load of 1200 kg at its free end and vertical stirrups can carry 1800 kg. Assuming concrete to carry one-third of the diagonal tension and ignoring the weight of the beam, the number of shear stirrups required, is
Discussion:
17 comments Page 1 of 2.
Abhi said:
1 decade ago
What is the formula?
Shamoa sadhukhan said:
1 decade ago
How it proof please explain?
Devi said:
10 years ago
Please explain me.
K.k said:
10 years ago
How to solve?
Rahul said:
9 years ago
Please explain.
Akash said:
9 years ago
Min spacing criteria are 1)7.5d, 2)300 we use a min of above.
Here the diameter of stirrups which is 6mm min so 6 x 7.5 =45 #so spacing we conveniently take 40.
Here the diameter of stirrups which is 6mm min so 6 x 7.5 =45 #so spacing we conveniently take 40.
Shailendra said:
9 years ago
@Akash.
Spacing is 0.75d where d is effective depth not Diameter.
Spacing is 0.75d where d is effective depth not Diameter.
Raju said:
8 years ago
Explain the answer.
Elumalai said:
8 years ago
Please explain the answer with formula.
(1)
Gubendhiran said:
8 years ago
When stress less than 5kg/cm2.
The Spacing of strippers is taken as the Lever's arm so 40cm is correct.
The Spacing of strippers is taken as the Lever's arm so 40cm is correct.
(3)
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