Discussion :: RCC Structures Design - Section 2 (Q.No.12)
|Abhi said: (Dec 28, 2014)|
|What is the formula?|
|Shamoa Sadhukhan said: (Aug 6, 2015)|
|How it proof please explain?|
|Devi said: (Sep 9, 2015)|
|Please explain me.|
|K.K said: (Oct 5, 2015)|
|How to solve?|
|Rahul said: (Aug 23, 2016)|
|Akash said: (Sep 28, 2016)|
|Min spacing criteria are 1)7.5d, 2)300 we use a min of above.
Here the diameter of stirrups which is 6mm min so 6 x 7.5 =45 #so spacing we conveniently take 40.
|Shailendra said: (Dec 5, 2016)|
Spacing is 0.75d where d is effective depth not Diameter.
|Raju said: (Apr 16, 2017)|
|Explain the answer.|
|Elumalai said: (May 20, 2017)|
|Please explain the answer with formula.|
|Gubendhiran said: (Aug 22, 2017)|
|When stress less than 5kg/cm2.
The Spacing of strippers is taken as the Lever's arm so 40cm is correct.
|Ritss said: (Dec 7, 2017)|
|Please explain in detail.|
|Sunil Kumar Meher said: (Apr 1, 2018)|
|Please explain it.|
|Kinagi said: (Apr 5, 2020)|
|Please explain in detail anyone?|
|Bilal Butt said: (Dec 16, 2020)|
|Clear Spacing from either sides of the beam is L/4, i.e, 360/4 = 90 mm.
Now, No. Of Stirrups = L/ spacing = 3600/90 = 40.
The answer is C.
|Engr Zaid said: (Apr 18, 2021)|
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