Civil Engineering - RCC Structures Design - Discussion

39. 

An R.C.C beam of 25 cm width has a clear span of 5 metres and carries a U.D.L. of 2000 kg/m inclusive of its self weight. If the lever arm of the section is 45 cm., the beam is

[A]. safe in shear
[B]. is safe with stirrups
[C]. is safe with stirrups and inclined members
[D]. needs revision of the section.

Answer: Option A

Explanation:

No answer description available for this question.

Engbaseem said: (Jul 16, 2016)  
How to check that?

Ankit said: (Aug 8, 2016)  
Someone please solve it?

Shailendra Kumar said: (Dec 5, 2016)  
SF = 2000 ÷ (500 * 100) = 0.04 kg/sq cm.
Safe shearing stress = L/A
Load = 20 * 500 = 10000 kg.
Area = 25 * 45 = 1125 sq cm.
Therefore L/A = 8.88 kg/sqcm.

Hence Safe shearing stress > shear force.
Result : Beam is safe in shear.

Gubendhiran said: (Aug 22, 2017)  
Shear stress=SF/(leverage X d).
SF=wl/4 = (2000*5)/4 =5000kg.

Shear stress=5000/(45*25)=4.44kg/cm^2 which is less than 5kg/cm^2 hence SAFE in shear stress.

Xiya said: (Nov 24, 2018)  
According to me, the Answer should be B.

Safe with stirrups.

Hardik. said: (Apr 11, 2020)  
@ Gubendhiran.

Its wl/2..
=(2000 * 5)/2 =5000 kg..

Mjm Gcek said: (Jul 24, 2021)  
Yes agreed with All, safe with stirrups is right.

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