Civil Engineering - RCC Structures Design - Discussion

Discussion Forum : RCC Structures Design - Section 1 (Q.No. 12)
12.
If a bent tendon is required to balance a concentrated load W at the centre of the span L, the central dip h must be at least
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.

Harshit said:   1 decade ago
P*e = Wl/4.

Bent tendon should be same as bending moment.

Subrata manna said:   1 decade ago
Please describe more.

Naveed said:   1 decade ago
What is p in above answer?

Nira said:   1 decade ago
P is load expressed in w.

Harish said:   1 decade ago
W for P ok then how for e=l/4 comes?

PIYUSH SINGH said:   1 decade ago
P is the prestressing tensile force given to the tendon or stressing wire which transfer the stress to the concrete either by adhesion (in case of prestressed pretension) or by anchorage (in case of posttensioned prestress) , Generally the wire/strand/tension is high tensile steel with tensile strength upto 1850 N/mm^2,

Concept is known as load balancing concept in which bending moment is balanced with the prestressing force.

Thus bending moment = Prestressing moment.

Wl/4 = P*h.

H = WL/4P.

Rupesh said:   9 years ago
Thanks @Piyush Singh.

Yamanoor said:   9 years ago
Ra * L = W * L/2,
Ra = WL/2,
Moment at center (Central dip) = Ra * L/2,
Then hp = w/2 * l/2,
= wl/4,
So, h = wl/4p.

Shaifali said:   9 years ago
What is central dip here?

Rishav karan said:   9 years ago
Shift at any point = external moment/Prestressing force.
EM= wl/4 (for concentrated load),
Where.
Prestressing force = P.
Thus, shift at center = wl/4P.


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