Civil Engineering - RCC Structures Design - Discussion

Discussion Forum : RCC Structures Design - Section 1 (Q.No. 12)
12.
If a bent tendon is required to balance a concentrated load W at the centre of the span L, the central dip h must be at least
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.

Mukesh said:   3 years ago
What is dip? Please explain. @Shaifali.

Sameer sopori said:   7 years ago
Bending moment For a beam with point load = WL/4.
Now, Prestressing force = P * h.
P*h=WL/4,
h=WL/P4.
(1)

Yasir said:   7 years ago
The prestressing moment(p*e) must develop the deflection of h=wl/4p.

Solution :p*h(e at Centre) =wl/4 (deflection due to point load at center).
(1)

Rishav karan said:   9 years ago
Shift at any point = external moment/Prestressing force.
EM= wl/4 (for concentrated load),
Where.
Prestressing force = P.
Thus, shift at center = wl/4P.

Shaifali said:   9 years ago
What is central dip here?

Yamanoor said:   9 years ago
Ra * L = W * L/2,
Ra = WL/2,
Moment at center (Central dip) = Ra * L/2,
Then hp = w/2 * l/2,
= wl/4,
So, h = wl/4p.

Rupesh said:   9 years ago
Thanks @Piyush Singh.

PIYUSH SINGH said:   1 decade ago
P is the prestressing tensile force given to the tendon or stressing wire which transfer the stress to the concrete either by adhesion (in case of prestressed pretension) or by anchorage (in case of posttensioned prestress) , Generally the wire/strand/tension is high tensile steel with tensile strength upto 1850 N/mm^2,

Concept is known as load balancing concept in which bending moment is balanced with the prestressing force.

Thus bending moment = Prestressing moment.

Wl/4 = P*h.

H = WL/4P.

Harish said:   1 decade ago
W for P ok then how for e=l/4 comes?

Nira said:   1 decade ago
P is load expressed in w.


Post your comments here:

Your comments will be displayed after verification.