Civil Engineering - RCC Structures Design - Discussion

Discussion Forum : RCC Structures Design - Section 3 (Q.No. 50)
50.
The diameter of transverse reinforcement of columns should be equal to one-fourth of the diameter of the main steel rods but not less than
4 mm
5 mm
6 mm
7 mm
8 mm
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
31 comments Page 2 of 4.

Soumen said:   8 years ago
If the dia is 16 mm then stirrup is 5mm.
If the dia is 20 mm then 6 mm.
So, min is 5 mm.

Silverheaven said:   8 years ago
According to IS code 5 mm correct.

Ritu said:   8 years ago
According to IS Code.

It was 5 mm and now it is 6 mm.

Uttam said:   8 years ago
As per working state method 5 mm.

Limit state method 6 mm.

Akash Awasare said:   8 years ago
The Correct Ans: 3) 6mm.

Remark: IS 456:2000, Cl. 26.5.3.2, c), 2).

Abhishek said:   8 years ago
According to IS 456 cl 26.5.3.2 part C.2

The diameter of the polygonal links or lateral ties shall be not less than one fourth of the diameter of the largest longitudinal bar and in no case less than 16 mm.

Yes it says 16 mm

And books says 6 mm

I have checked the code on archive.org

Someone, please tell me why IS code saying 16 mm?

Jivan shrestha said:   7 years ago
IS 456:2000, Cl. 26.5.3.2, c), 2).

So, it is 6mm.

Ijom ninu nino said:   7 years ago
@Abhishek.

In IS code, 16 mm is just a misprinting, its 6mm.

Vibha said:   7 years ago
You are right @Nino.

6mm is right.

Sidd said:   7 years ago
The correct answer is 7.

Listen, Dia should be maximum of 1/4th of dia or 6mm.

But it is given in QS that. If dia will b 1/4th of dia of the main bar then it means it can't be 6 mm. It can be 7 or greater than that. So the answer is D.
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