Civil Engineering - Railways - Discussion
Discussion Forum : Railways - Section 4 (Q.No. 13)
13.
If the standard length of a B.G. crossing is 597 cm, the number of crossing, is
Discussion:
9 comments Page 1 of 1.
Hardinge said:
2 years ago
Here is the full explanation for this question.
It's not based on any formula but rather directly on RDSO and IRCEN values given in their publication known as "Turnout" wherein if you see Annexure 8 and Annexure 9 table and see the values of Length for Built-up Crossings(not CMS Crossing) you'll see that they are 4800mm and 5970mm for BG for 1 in 8.5 and 1in 12 respectively.
Also, for MG it's 4800mm for both 1 in 8.5 and 1 in 12 (for Built-up Crossing).
So for BG @4800mm - 1 in 8.5,
For MG @4800mm - 1 in 8.5,
For BG @5970mm - 1 in 12.
For MG @4800mm - 1 in 12 here.
It's not based on any formula but rather directly on RDSO and IRCEN values given in their publication known as "Turnout" wherein if you see Annexure 8 and Annexure 9 table and see the values of Length for Built-up Crossings(not CMS Crossing) you'll see that they are 4800mm and 5970mm for BG for 1 in 8.5 and 1in 12 respectively.
Also, for MG it's 4800mm for both 1 in 8.5 and 1 in 12 (for Built-up Crossing).
So for BG @4800mm - 1 in 8.5,
For MG @4800mm - 1 in 8.5,
For BG @5970mm - 1 in 12.
For MG @4800mm - 1 in 12 here.
(3)
Kamesh said:
4 years ago
Thanks @Anish Kumar.
Anish kumar said:
5 years ago
Number of crossing = Length of crossing/0.5.
So, No of crossing = 5.97/0.5 = 12,
597cm = 5.97m.
So, No of crossing = 5.97/0.5 = 12,
597cm = 5.97m.
(3)
Masum said:
5 years ago
Anyone, explain this in detail.
(1)
Prakhar said:
7 years ago
Please explains with formula.
(1)
Vishal said:
7 years ago
Please explain.
Shaad said:
7 years ago
Please explain the answer.
(1)
Bapuji said:
7 years ago
Explain this answer in detail.
Abhi said:
8 years ago
Someone explain this with formula.
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