Civil Engineering - Railways - Discussion
Discussion Forum : Railways - Section 1 (Q.No. 2)
2.
If absolute levels of rails at the consecutive axles A, B, and C separated by 1.8 metres are 100.505 m, 100.530 m, and 100.525 m respectively, the unevenness of rails, is
Discussion:
33 comments Page 2 of 4.
Sandeep Ahirwar said:
8 years ago
Please explain the answer clearly.
Vikas mahto said:
8 years ago
Please give solution clearly.
Amu bokato said:
7 years ago
I am not getting this. Please, anyone explain it in clearly.
Manju said:
7 years ago
Please anyone explain in detail.
Prakash said:
9 years ago
100.505,100.530,100.525 level.
.505, .530, .525.
0.005 + 0.030 + 0.025 = 0.060 m.
.505, .530, .525.
0.005 + 0.030 + 0.025 = 0.060 m.
Aamir Ashraf said:
5 years ago
Unevenness - The longitudinal unevenness of rails is measured as a deviation in the vertical plane (depression or rise) of the middle axle of the measuring bogie with reference to the average position of the two outer axles.
The outer axles are spaced 3.6 metres apart and unevenness is recorded to a scale of 1:1 on a base of 3.6 M for left and right rail separately.
The outer axles are spaced 3.6 metres apart and unevenness is recorded to a scale of 1:1 on a base of 3.6 M for left and right rail separately.
Karolin said:
1 month ago
Unevenness = A + C − 2B.
= 100.505 + 100.525 − 2(100.530).
= 201.030 − 201.060 = −0.030.
Magnitude: 0.030 m
So, the answer should be 0.030 m, not 0.065 m.
= 100.505 + 100.525 − 2(100.530).
= 201.030 − 201.060 = −0.030.
Magnitude: 0.030 m
So, the answer should be 0.030 m, not 0.065 m.
Ajay Khodake said:
1 decade ago
Why this is answer?
Pooja said:
10 years ago
Please solve this question with an explanation.
Rajesh Badugu said:
10 years ago
Find mean of all, you ll get 100.520
Unevenness = |100.505 - 100.520| + |100.530 - 100.520| + |100.525 - 100.520| divided by 1.8 = 0.063888.
Unevenness = |100.505 - 100.520| + |100.530 - 100.520| + |100.525 - 100.520| divided by 1.8 = 0.063888.
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