Civil Engineering - Railways - Discussion
Discussion Forum : Railways - Section 2 (Q.No. 13)
13.
If sleeper density is M + 7 for 13 m rails, the minimum depth of ballast under wooden sleepers (25 cm x 13 cm), is
Discussion:
15 comments Page 2 of 2.
Priya said:
9 years ago
Sleeper density is m+7.
Length is 13m.
Therefore spacing = m/(m + 7) = 13/(13 + 7).
= 0.65m = 65 cm.
Width w = 25cm.
Therefore depth = (s - w)/2 =(65 - 25)/2 = 20cm.
Length is 13m.
Therefore spacing = m/(m + 7) = 13/(13 + 7).
= 0.65m = 65 cm.
Width w = 25cm.
Therefore depth = (s - w)/2 =(65 - 25)/2 = 20cm.
(3)
LIPPUN said:
10 years ago
Spacing bet^n Sleeper = w/2+2Db+w/2.
S = 13/(13+7) = 65, w = 65. Then from above formula Db = 20 cm.
S = 13/(13+7) = 65, w = 65. Then from above formula Db = 20 cm.
Taimoor Hassan Babar said:
10 years ago
Its a sleeper density. Not a depth of ballast?
What will be the depth of ballast?
What will be the depth of ballast?
Taimoor Hassan Babar said:
10 years ago
Its a sleeper density. Not a depth of ballast?
What will be the depth of ballast?
What will be the depth of ballast?
Sourov Roy said:
1 decade ago
Here,
Sleeper Density = N+X,
M = Length of one Rail in meter = 13.
X = Excess number of Sleeper = 7.
Sleeper Density = 7+13 = 20.
Sleeper Density = N+X,
M = Length of one Rail in meter = 13.
X = Excess number of Sleeper = 7.
Sleeper Density = 7+13 = 20.
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