Civil Engineering - Hydraulics - Discussion

Discussion Forum : Hydraulics - Section 1 (Q.No. 16)
16.
The ratio of maximum velocity to average velocity of viscous fluid through a circular pipe is
0.5
0.75
1.25
2.00
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 2 of 3.

Mahesh Walde said:   8 years ago
Boss maximum velocity is 0.97 and avg velocity is 0.81 then how become its ratio 2?

Sahil Sanjeev Salvi said:   8 years ago
Max. Velocity = 2 Avg. Velocity --> For Pipe.
Max. Velocity = 1.5 Avg. Velocity --> For Plate.

Michelle Mencias said:   8 years ago
If you solve this question for the laminar case the maximum velocity will be 2*uavg, 2*uavg, this means chaotic system dissipate more energy due to viscous effect. And can be related to the natural phenomenon as big eddies that form in the fluid consumes energy in form of angular velocity or vorticity and get converted to smaller eddies and eventually die out dissipating energy to the environment.

Venkatesh naidu said:   8 years ago
In laminar flow, for pipes max.velocity= 2*avg.velocity.
For parallel plates max.velocity=1.50*avg.velocity.
(1)

Parrro said:   8 years ago
Please, Explain the process.

Lalitha said:   7 years ago
Not getting the solution, Please explain clearly.

Bhanu said:   7 years ago
Max.velocity= - 1 ÷ 4u (dp ÷ dx)*r^2
And avg. Velocity = -1 ÷8u (dp ÷ dx)*-r^2, so that the ratio will be = 2.

Adie said:   7 years ago
The answer is 3/2 or 1.25 for circular pipes.

Chandan Rakha said:   7 years ago
@Adie.

No, it's for plates 1.25.

Harshit said:   6 years ago
Vmax/Vavg = 2 for laminar circular pipe flow.
.
.
.
Vmax/Vavg = 3/2 for laminar fixed plate flow.
(3)


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