Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 21)
21.
A cylinder 3 m in diameter and 4 m long retains water one side as shown in the below figure. If the weight of the cylinder is 2000 kgf, the horizontal reaction at B is
Discussion:
22 comments Page 2 of 3.
Rabinarayan Hota said:
7 years ago
Here, area =3*4 taken as it is the Projected area.
(1)
Nami said:
7 years ago
@Jitendra.
How 1.5/2? Please explain in detail.
How 1.5/2? Please explain in detail.
(1)
Jitendra said:
7 years ago
F=wAh,
=2000*(3*4)*1.5/2,
=18000kgf.
=2000*(3*4)*1.5/2,
=18000kgf.
(1)
Sharma said:
7 years ago
Here area taken as (3*4) is the projected area on vertical plane.
Yossri said:
8 years ago
I agree @Sagar Radadiya.
Pressure at middle of pipe = pgh.
= 1000*9.81*1.5 (pressure is min. at depth 0 & max. at depth 3m, so average 1.5m is taken).
= 14715 kg/sq. mt.
So, Force at B = Pressure * Area.
= 14715*(3*4),
= 176580 N,
= 176580/9.81 kgf,
= 18000 kgf.
Pressure at middle of pipe = pgh.
= 1000*9.81*1.5 (pressure is min. at depth 0 & max. at depth 3m, so average 1.5m is taken).
= 14715 kg/sq. mt.
So, Force at B = Pressure * Area.
= 14715*(3*4),
= 176580 N,
= 176580/9.81 kgf,
= 18000 kgf.
Arshad Nirwan said:
8 years ago
3 meter (dia of pipe) also known as (hight),
4 meter long (size of pipe) also known as (length),
So, horizontal area is = height * length (3 * 4)=12.
4 meter long (size of pipe) also known as (length),
So, horizontal area is = height * length (3 * 4)=12.
Samynathan said:
8 years ago
How horizontal area is 3*4?
Sagar Radadiya said:
8 years ago
Pressure at middle of pipe = pgh.
= 1000*9.81*1.5 (pressure is min. at depth 0 & max. at depth 3m, so average 1.5m is taken).
= 14715 kg/sq. mt.
So, Force at B = Pressure * Area.
= 14715*(3*4),
= 176580 N,
= 176580/9.81 kgf,
= 18000 kgf.
= 1000*9.81*1.5 (pressure is min. at depth 0 & max. at depth 3m, so average 1.5m is taken).
= 14715 kg/sq. mt.
So, Force at B = Pressure * Area.
= 14715*(3*4),
= 176580 N,
= 176580/9.81 kgf,
= 18000 kgf.
Rizgar Karim said:
1 decade ago
Specific weight of water = 9.81 KN/m3.
Horizontal area = 3*4 = 12 m2.
Depth of center of gravity from the water surface = 3/2 = 1.5 m.
Horizontal force = Reaction at B = 9.81*12*1.5 = 176.58 KN/m2.
= 176.58*1000 = 176580 N/m2.
= 176580/9.81 = 18000 Kgf.
Horizontal area = 3*4 = 12 m2.
Depth of center of gravity from the water surface = 3/2 = 1.5 m.
Horizontal force = Reaction at B = 9.81*12*1.5 = 176.58 KN/m2.
= 176.58*1000 = 176580 N/m2.
= 176580/9.81 = 18000 Kgf.
Ratan said:
1 decade ago
Horizontal force F = whA.
w = 1000*g.
A = 3*4 = 12 m2.
h = 3/2.
F = 1000*12*1.5*g = 18000kgf.
w = 1000*g.
A = 3*4 = 12 m2.
h = 3/2.
F = 1000*12*1.5*g = 18000kgf.
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