Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 21)
21.
A cylinder 3 m in diameter and 4 m long retains water one side as shown in the below figure. If the weight of the cylinder is 2000 kgf, the horizontal reaction at B is
Discussion:
22 comments Page 1 of 3.
Sagar Radadiya said:
8 years ago
Pressure at middle of pipe = pgh.
= 1000*9.81*1.5 (pressure is min. at depth 0 & max. at depth 3m, so average 1.5m is taken).
= 14715 kg/sq. mt.
So, Force at B = Pressure * Area.
= 14715*(3*4),
= 176580 N,
= 176580/9.81 kgf,
= 18000 kgf.
= 1000*9.81*1.5 (pressure is min. at depth 0 & max. at depth 3m, so average 1.5m is taken).
= 14715 kg/sq. mt.
So, Force at B = Pressure * Area.
= 14715*(3*4),
= 176580 N,
= 176580/9.81 kgf,
= 18000 kgf.
Yossri said:
8 years ago
I agree @Sagar Radadiya.
Pressure at middle of pipe = pgh.
= 1000*9.81*1.5 (pressure is min. at depth 0 & max. at depth 3m, so average 1.5m is taken).
= 14715 kg/sq. mt.
So, Force at B = Pressure * Area.
= 14715*(3*4),
= 176580 N,
= 176580/9.81 kgf,
= 18000 kgf.
Pressure at middle of pipe = pgh.
= 1000*9.81*1.5 (pressure is min. at depth 0 & max. at depth 3m, so average 1.5m is taken).
= 14715 kg/sq. mt.
So, Force at B = Pressure * Area.
= 14715*(3*4),
= 176580 N,
= 176580/9.81 kgf,
= 18000 kgf.
Rizgar Karim said:
1 decade ago
Specific weight of water = 9.81 KN/m3.
Horizontal area = 3*4 = 12 m2.
Depth of center of gravity from the water surface = 3/2 = 1.5 m.
Horizontal force = Reaction at B = 9.81*12*1.5 = 176.58 KN/m2.
= 176.58*1000 = 176580 N/m2.
= 176580/9.81 = 18000 Kgf.
Horizontal area = 3*4 = 12 m2.
Depth of center of gravity from the water surface = 3/2 = 1.5 m.
Horizontal force = Reaction at B = 9.81*12*1.5 = 176.58 KN/m2.
= 176.58*1000 = 176580 N/m2.
= 176580/9.81 = 18000 Kgf.
Sonu said:
6 years ago
Here vertical due to water on the cylinder is cancel out. So that resultant vertical force equal to the weight of the cylinder.
Then horizontal force equal to the volume of pressure diagram i.e.
= (1/2)*3*1000*3*4.
= 18000kgf.
Then horizontal force equal to the volume of pressure diagram i.e.
= (1/2)*3*1000*3*4.
= 18000kgf.
(4)
Zakir said:
4 years ago
Horizontal projected area = 3 * 4=12 m2.
Total horizontal triangular force= 0.5* 3000* 3=4500 kgf per m strip of cylinder,
Hence, the total force = 4500* 4 = 18000 kgf.
Total horizontal triangular force= 0.5* 3000* 3=4500 kgf per m strip of cylinder,
Hence, the total force = 4500* 4 = 18000 kgf.
(6)
Arshad Nirwan said:
8 years ago
3 meter (dia of pipe) also known as (hight),
4 meter long (size of pipe) also known as (length),
So, horizontal area is = height * length (3 * 4)=12.
4 meter long (size of pipe) also known as (length),
So, horizontal area is = height * length (3 * 4)=12.
Inayat Ullah Kakar said:
9 months ago
I think it's simple;
Horizontal force = wAx.
w = density × g.
Density of water = 1000 kg/cum
x = 3/2.
A = 3×4,
F = 1000× g×3×4×3/2.
F = 18000kgf.
Horizontal force = wAx.
w = density × g.
Density of water = 1000 kg/cum
x = 3/2.
A = 3×4,
F = 1000× g×3×4×3/2.
F = 18000kgf.
(4)
Ratan said:
1 decade ago
Horizontal force F = whA.
w = 1000*g.
A = 3*4 = 12 m2.
h = 3/2.
F = 1000*12*1.5*g = 18000kgf.
w = 1000*g.
A = 3*4 = 12 m2.
h = 3/2.
F = 1000*12*1.5*g = 18000kgf.
Sharma said:
7 years ago
Here area taken as (3*4) is the projected area on vertical plane.
Rabinarayan Hota said:
7 years ago
Here, area =3*4 taken as it is the Projected area.
(1)
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