Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 21)
21.
A cylinder 3 m in diameter and 4 m long retains water one side as shown in the below figure. If the weight of the cylinder is 2000 kgf, the horizontal reaction at B is
Discussion:
22 comments Page 1 of 3.
Zakir said:
4 years ago
Horizontal projected area = 3 * 4=12 m2.
Total horizontal triangular force= 0.5* 3000* 3=4500 kgf per m strip of cylinder,
Hence, the total force = 4500* 4 = 18000 kgf.
Total horizontal triangular force= 0.5* 3000* 3=4500 kgf per m strip of cylinder,
Hence, the total force = 4500* 4 = 18000 kgf.
(6)
Inayat Ullah Kakar said:
9 months ago
I think it's simple;
Horizontal force = wAx.
w = density × g.
Density of water = 1000 kg/cum
x = 3/2.
A = 3×4,
F = 1000× g×3×4×3/2.
F = 18000kgf.
Horizontal force = wAx.
w = density × g.
Density of water = 1000 kg/cum
x = 3/2.
A = 3×4,
F = 1000× g×3×4×3/2.
F = 18000kgf.
(4)
Ladla malik said:
5 years ago
Answer is 18000kgf.
(4)
Sonu said:
6 years ago
Here vertical due to water on the cylinder is cancel out. So that resultant vertical force equal to the weight of the cylinder.
Then horizontal force equal to the volume of pressure diagram i.e.
= (1/2)*3*1000*3*4.
= 18000kgf.
Then horizontal force equal to the volume of pressure diagram i.e.
= (1/2)*3*1000*3*4.
= 18000kgf.
(4)
Rabinarayan Hota said:
7 years ago
Here, area =3*4 taken as it is the Projected area.
(1)
Abhik said:
6 years ago
How Area is 3 * 4? It's a cylinder.
(1)
Divya said:
7 years ago
Centre of gravity.
So, the depth divided by 2.
So, the depth divided by 2.
(1)
Nami said:
7 years ago
@Jitendra.
How 1.5/2? Please explain in detail.
How 1.5/2? Please explain in detail.
(1)
Jitendra said:
7 years ago
F=wAh,
=2000*(3*4)*1.5/2,
=18000kgf.
=2000*(3*4)*1.5/2,
=18000kgf.
(1)
Sharma said:
7 years ago
Here area taken as (3*4) is the projected area on vertical plane.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers