Civil Engineering - Hydraulics - Discussion

Discussion Forum : Hydraulics - Section 1 (Q.No. 5)
5.
If the atmospheric pressure on the surface of an oil tank (sp. gr. 0.8) is 0.1 kg/cm2, the pressure at a depth of 2.5 m, is
1 metre of water
2 metres of water
3 metres of water
3.5 metres of water
4.0 metres of water.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
42 comments Page 4 of 5.

Prashant said:   7 years ago
How (total pressure/atm pressure) is equal to the pressure head of water?

Please explain anyone.

Thanks.

WAQAR AHMED AWAN said:   8 years ago
We know that;

1kg=9.81N and 1m=100cm.
let atmosppheric pressure at top surface be; P1=denssity*g*h=0.1kg/cm2=0.1*9.81*100*100=9810N/m2.
let pressure at heigt of 2.5m be p2=0.8*1000*9.81*2.5=19620N/M2.
now total pressureP =p1+p2=9810+19620=29430N/m2.
NOW pressure in terms of water =P/p1=29430/9810=3m so option C is correct.

Gurmeet said:   8 years ago
Simply P = density * gh.

Suresh yadav said:   8 years ago
Yes, your answer is correct. Thank you @Dipesh.

Makar said:   8 years ago
Yes, correct @Dipesh.

Makar said:   8 years ago
1 kg/m2 = 1000kg/cm2 this are correct.

Er. Dipesh yadav said:   8 years ago
Atmospheric pressure = 0.1 * 9.81 * 100 * 100 = 9810 N/m2.
Pressure at 2.5m depth = 0.8 * 9810 * 2.5 = 19620 N/m2.
Total pressure at depth 2.5m = 9810 + 19620 = 29430 N/m2.
Height in terms of water= 29430/9810 = 3m.

Sashaus said:   8 years ago
S1 h1 = s2 h2 or £1h1 = £2h2.
£ = density , s= sp.gr.

1000 h1 = 800 * 2.5.
H1 = 2 + 1 (initially pressure is 1) = 3.

Jeevan said:   8 years ago
Specific Gravity of oil is .8 & water is 1. So oil has less density the water therefor, water shows less head. So, the answer will be 2m not 3.

Anonymous said:   8 years ago
I think the answer should be 2 m. Because the atm pressure will be same for both oil surface and water surface. So it will be neglected.

Please reply if anyone thinks I'm wrong. And do explain. Thanks.


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