Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 5)
5.
If the atmospheric pressure on the surface of an oil tank (sp. gr. 0.8) is 0.1 kg/cm2, the pressure at a depth of 2.5 m, is
Discussion:
42 comments Page 3 of 5.
MA MURTAZA said:
1 decade ago
p*ATM = 0.1 kg/cm*2 = 1000 kg/m*2 = 9810 N/m*2.
p*oil = 19620 N/m*2 (after calculation).
Total pressure = 29430 N/m*2.
Hence, h*water = 29430/9810 = 3 m of water.
p*oil = 19620 N/m*2 (after calculation).
Total pressure = 29430 N/m*2.
Hence, h*water = 29430/9810 = 3 m of water.
Abdilahi khalif said:
1 decade ago
1000/(1000+2.5*0.8) = 3.
Vikas said:
5 years ago
If we will consider the value of g then the pressure will come in the unit of Newton/square meter.
For determining the value of pressure in the form of kg/m2 we can't use Value of g.
For determining the value of pressure in the form of kg/m2 we can't use Value of g.
Pavan said:
5 years ago
How the pressure at 250 cm comes out as 2000 Kg/m2?
That will be $gh, we don't consider 'g' value.
Can anyone explain me?
That will be $gh, we don't consider 'g' value.
Can anyone explain me?
Pawan pandey said:
5 years ago
0.1*10^4 kg/m2= 1000 kg/m2.
0.8*1000*2.5= 2000 kg/m2,
1000+2000= 3000 kg/m2 ( pressure ),
3000/1000= 3 m of water.
0.8*1000*2.5= 2000 kg/m2,
1000+2000= 3000 kg/m2 ( pressure ),
3000/1000= 3 m of water.
Ravinder said:
5 years ago
Patm=0.1kg/cm^2=10,000Kg/m^2.
Pressure at 2.5m=0.8*1000*0.8*2.5=19620Kg/m^2.
Total pressure at 2.5m=10,000+19620=29620Kg/m^2.
But in option, we need pressure in terms of head=Pressure/(Density*g)
H=29620/(9.81*1000)=3.1~3m of water column.
Pressure at 2.5m=0.8*1000*0.8*2.5=19620Kg/m^2.
Total pressure at 2.5m=10,000+19620=29620Kg/m^2.
But in option, we need pressure in terms of head=Pressure/(Density*g)
H=29620/(9.81*1000)=3.1~3m of water column.
Saurabh kaday said:
5 years ago
Don't understand clearly.
Anyone, please solve it by standard formula with step by step with meaning.
Anyone, please solve it by standard formula with step by step with meaning.
Rizgar Karim said:
1 decade ago
Patm = 0.1kg/cm2 = 0.1*10000*9.81/1000 = 9.81 KN/m2.
Poil = 0.8*9.81*2.5 = 19.62 KN/m2.
Ptotal = Patm + Poil.
Ptotal = 19.62 + 9.81 = 29.43 KN/m2.
P in-term of water = 29.43/9.81 = 3m of water.
Poil = 0.8*9.81*2.5 = 19.62 KN/m2.
Ptotal = Patm + Poil.
Ptotal = 19.62 + 9.81 = 29.43 KN/m2.
P in-term of water = 29.43/9.81 = 3m of water.
Bahram said:
9 years ago
First Patm = 0.1kg/sq/cm = 1000 kg/sq.m.
Now Poil = S(oil) * ρ(water) *h(oil) => 0.8 * 1000 * 2.5 = 2,000 kg/sq.m.
So, P(total at bottom) = 2,000 + 1,000 = 3,000 kg/sq.m.
Now h(pressure in terms of head of water) = P(total)/ρ(water) => 3,000 kg/sq.m/1,000 kg/cu.m = 3 m of water.
Now Poil = S(oil) * ρ(water) *h(oil) => 0.8 * 1000 * 2.5 = 2,000 kg/sq.m.
So, P(total at bottom) = 2,000 + 1,000 = 3,000 kg/sq.m.
Now h(pressure in terms of head of water) = P(total)/ρ(water) => 3,000 kg/sq.m/1,000 kg/cu.m = 3 m of water.
Anonymous said:
9 years ago
P2 = P1 + Density(H); P1 = 0.1kg/cm^2 or 1000kg/m2.
Density of oil = specific Gravity x 1000 kg/m3.
= 800kg/m3 (Note: 1000kg/m3 is the density of water).
P2 = 1000 + 800 x 2.5 = 3000kg/m2.
Pressure in H of Water = 3000/1000 = 3.0m.
Density of oil = specific Gravity x 1000 kg/m3.
= 800kg/m3 (Note: 1000kg/m3 is the density of water).
P2 = 1000 + 800 x 2.5 = 3000kg/m2.
Pressure in H of Water = 3000/1000 = 3.0m.
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