Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 5)
5.
If the atmospheric pressure on the surface of an oil tank (sp. gr. 0.8) is 0.1 kg/cm2, the pressure at a depth of 2.5 m, is
Discussion:
42 comments Page 5 of 5.
Rajani patel said:
9 years ago
Pressure at surface =10000kg/m^2.
Pressure at a depth of 2.5 m=(2.5*9.81*800)=19620.
Total pressure=29620.
H=P/1000*9.81=29620/1000*9.81.
H = 3.01m of water.
Pressure at a depth of 2.5 m=(2.5*9.81*800)=19620.
Total pressure=29620.
H=P/1000*9.81=29620/1000*9.81.
H = 3.01m of water.
Kailash paliwal said:
9 years ago
Atmosphere pressure =.1kg/cm2 = 1000 kg/m2.
1000kg/1000kg = 1m of water.
Oil pressure = 2.5m = 2.5 *.8 = 2m of water. Total height = 1 + 2 = 3 m. Hence c is right.
1000kg/1000kg = 1m of water.
Oil pressure = 2.5m = 2.5 *.8 = 2m of water. Total height = 1 + 2 = 3 m. Hence c is right.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers