Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 5)
5.
If the atmospheric pressure on the surface of an oil tank (sp. gr. 0.8) is 0.1 kg/cm2, the pressure at a depth of 2.5 m, is
Discussion:
42 comments Page 3 of 5.
KUMAR said:
1 decade ago
Initial pressure is 1000 kg/m^2.
Pressure at 2.5 m depth is 19620 kg/m^2.
Total pressure at a depth 2.5 m is = 19620+1000 = 20620 kg/m^2.
Depth in terms of water = 20620/(1000*9.81) = 2.1 m.
Pressure at 2.5 m depth is 19620 kg/m^2.
Total pressure at a depth 2.5 m is = 19620+1000 = 20620 kg/m^2.
Depth in terms of water = 20620/(1000*9.81) = 2.1 m.
Vikas said:
5 years ago
If we will consider the value of g then the pressure will come in the unit of Newton/square meter.
For determining the value of pressure in the form of kg/m2 we can't use Value of g.
For determining the value of pressure in the form of kg/m2 we can't use Value of g.
Kailash paliwal said:
9 years ago
Atmosphere pressure =.1kg/cm2 = 1000 kg/m2.
1000kg/1000kg = 1m of water.
Oil pressure = 2.5m = 2.5 *.8 = 2m of water. Total height = 1 + 2 = 3 m. Hence c is right.
1000kg/1000kg = 1m of water.
Oil pressure = 2.5m = 2.5 *.8 = 2m of water. Total height = 1 + 2 = 3 m. Hence c is right.
MA MURTAZA said:
1 decade ago
p*ATM = 0.1 kg/cm*2 = 1000 kg/m*2 = 9810 N/m*2.
p*oil = 19620 N/m*2 (after calculation).
Total pressure = 29430 N/m*2.
Hence, h*water = 29430/9810 = 3 m of water.
p*oil = 19620 N/m*2 (after calculation).
Total pressure = 29430 N/m*2.
Hence, h*water = 29430/9810 = 3 m of water.
Rajani patel said:
9 years ago
Pressure at surface =10000kg/m^2.
Pressure at a depth of 2.5 m=(2.5*9.81*800)=19620.
Total pressure=29620.
H=P/1000*9.81=29620/1000*9.81.
H = 3.01m of water.
Pressure at a depth of 2.5 m=(2.5*9.81*800)=19620.
Total pressure=29620.
H=P/1000*9.81=29620/1000*9.81.
H = 3.01m of water.
Jeevan said:
8 years ago
Specific Gravity of oil is .8 & water is 1. So oil has less density the water therefor, water shows less head. So, the answer will be 2m not 3.
Komala sai said:
9 years ago
Patm = 0.1kg/cm^2
=> 1000kg/m^2.
Poil = (0.8 * 1000) * 2.5
= 2000 kg/m^2.
Finally in terms of water = (1000 + 2000) ÷ 1000,
= 3m of water.
=> 1000kg/m^2.
Poil = (0.8 * 1000) * 2.5
= 2000 kg/m^2.
Finally in terms of water = (1000 + 2000) ÷ 1000,
= 3m of water.
(1)
Sashaus said:
8 years ago
S1 h1 = s2 h2 or £1h1 = £2h2.
£ = density , s= sp.gr.
1000 h1 = 800 * 2.5.
H1 = 2 + 1 (initially pressure is 1) = 3.
£ = density , s= sp.gr.
1000 h1 = 800 * 2.5.
H1 = 2 + 1 (initially pressure is 1) = 3.
Pavan said:
5 years ago
How the pressure at 250 cm comes out as 2000 Kg/m2?
That will be $gh, we don't consider 'g' value.
Can anyone explain me?
That will be $gh, we don't consider 'g' value.
Can anyone explain me?
Pawan pandey said:
5 years ago
0.1*10^4 kg/m2= 1000 kg/m2.
0.8*1000*2.5= 2000 kg/m2,
1000+2000= 3000 kg/m2 ( pressure ),
3000/1000= 3 m of water.
0.8*1000*2.5= 2000 kg/m2,
1000+2000= 3000 kg/m2 ( pressure ),
3000/1000= 3 m of water.
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