Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 5)
5.
If the atmospheric pressure on the surface of an oil tank (sp. gr. 0.8) is 0.1 kg/cm2, the pressure at a depth of 2.5 m, is
Discussion:
42 comments Page 2 of 5.
Nani Abdul said:
7 years ago
Patm + (0.8)(2.5m)(9810N/m3) = Hh2o(9810N/m3).
Patm = 0.1Kg/cm2 --> 1000Kg/m2.
Patm = 1000Kg/m2(9.81m/s2) --> 9810N/m2 (Pa).
9810N/m2 + (0.8)(2.5m)(9810N/m3) = Hh2o(9810N/m3).
Hh20 = (9810N/m2 + (0.8)(2.5m)(9810N/m3))/9810N/m3.
Hh20 = 3mts.
Patm = 0.1Kg/cm2 --> 1000Kg/m2.
Patm = 1000Kg/m2(9.81m/s2) --> 9810N/m2 (Pa).
9810N/m2 + (0.8)(2.5m)(9810N/m3) = Hh2o(9810N/m3).
Hh20 = (9810N/m2 + (0.8)(2.5m)(9810N/m3))/9810N/m3.
Hh20 = 3mts.
(1)
Manpraveen said:
1 decade ago
P = $gh.
Pressure for oil = 0.8*1000*9.81*2.5 = 19620 n/m^2.
Pressure for water = 1000*9.81*h = 19620.
H1 = 19620/9810 = 2 m.
H2 = atmospheric head = p/$g.
H2 = 1000*9.81/1000*9.81= 1 m.
Total head = H1+H2 = 2+1 = 3 m (Answer).
Pressure for oil = 0.8*1000*9.81*2.5 = 19620 n/m^2.
Pressure for water = 1000*9.81*h = 19620.
H1 = 19620/9810 = 2 m.
H2 = atmospheric head = p/$g.
H2 = 1000*9.81/1000*9.81= 1 m.
Total head = H1+H2 = 2+1 = 3 m (Answer).
Ravinder said:
5 years ago
Patm=0.1kg/cm^2=10,000Kg/m^2.
Pressure at 2.5m=0.8*1000*0.8*2.5=19620Kg/m^2.
Total pressure at 2.5m=10,000+19620=29620Kg/m^2.
But in option, we need pressure in terms of head=Pressure/(Density*g)
H=29620/(9.81*1000)=3.1~3m of water column.
Pressure at 2.5m=0.8*1000*0.8*2.5=19620Kg/m^2.
Total pressure at 2.5m=10,000+19620=29620Kg/m^2.
But in option, we need pressure in terms of head=Pressure/(Density*g)
H=29620/(9.81*1000)=3.1~3m of water column.
Anonymous said:
9 years ago
P2 = P1 + Density(H); P1 = 0.1kg/cm^2 or 1000kg/m2.
Density of oil = specific Gravity x 1000 kg/m3.
= 800kg/m3 (Note: 1000kg/m3 is the density of water).
P2 = 1000 + 800 x 2.5 = 3000kg/m2.
Pressure in H of Water = 3000/1000 = 3.0m.
Density of oil = specific Gravity x 1000 kg/m3.
= 800kg/m3 (Note: 1000kg/m3 is the density of water).
P2 = 1000 + 800 x 2.5 = 3000kg/m2.
Pressure in H of Water = 3000/1000 = 3.0m.
Er. Dipesh yadav said:
8 years ago
Atmospheric pressure = 0.1 * 9.81 * 100 * 100 = 9810 N/m2.
Pressure at 2.5m depth = 0.8 * 9810 * 2.5 = 19620 N/m2.
Total pressure at depth 2.5m = 9810 + 19620 = 29430 N/m2.
Height in terms of water= 29430/9810 = 3m.
Pressure at 2.5m depth = 0.8 * 9810 * 2.5 = 19620 N/m2.
Total pressure at depth 2.5m = 9810 + 19620 = 29430 N/m2.
Height in terms of water= 29430/9810 = 3m.
Anonymous said:
9 years ago
I think the answer should be 2 m. Because the atm pressure will be same for both oil surface and water surface. So it will be neglected.
Please reply if anyone thinks I'm wrong. And do explain. Thanks.
Please reply if anyone thinks I'm wrong. And do explain. Thanks.
Govind said:
6 years ago
The pressure at the bottom is 2.5x0.8x9.81= 19.62 KN/M3.
Initial pressure at top= 0.1 kg/cm2= 0.1x98.06=9.80 KN/M3.
Total pressure at Bottom =19.62+9.80 =29.42 KN/M3.
Head= 29.4/9.81 =2.99 =3.00 Metre.
Initial pressure at top= 0.1 kg/cm2= 0.1x98.06=9.80 KN/M3.
Total pressure at Bottom =19.62+9.80 =29.42 KN/M3.
Head= 29.4/9.81 =2.99 =3.00 Metre.
(1)
Amrit said:
3 years ago
Pressure at 2.5m depth due to gravity = 2.5 * 0.8 = 2m of WC.
Pressure at surface = 0.1 kg/cm^2 = 1 m of WC (as 10 m WC = 1 kg/cm^2),
Hence, Total pressure at 2.5m depth = (2 + 1) m of WC = 3 m of WC.
Pressure at surface = 0.1 kg/cm^2 = 1 m of WC (as 10 m WC = 1 kg/cm^2),
Hence, Total pressure at 2.5m depth = (2 + 1) m of WC = 3 m of WC.
(1)
Jawad said:
3 years ago
P= atmospheric pressure + ρ*g*h.
P= 0.1 kg/cm2 + 0.8*1000*10*2.5=10000N/m2 +20000N/m2,
= 30000N/ m2.
Now convert into water head as,
30000= 1000*10* height of water.
Height of water = 3.
P= 0.1 kg/cm2 + 0.8*1000*10*2.5=10000N/m2 +20000N/m2,
= 30000N/ m2.
Now convert into water head as,
30000= 1000*10* height of water.
Height of water = 3.
(3)
Rizgar Karim said:
1 decade ago
Patm = 0.1kg/cm2 = 0.1*10000*9.81/1000 = 9.81 KN/m2.
Poil = 0.8*9.81*2.5 = 19.62 KN/m2.
Ptotal = Patm + Poil.
Ptotal = 19.62 + 9.81 = 29.43 KN/m2.
P in-term of water = 29.43/9.81 = 3m of water.
Poil = 0.8*9.81*2.5 = 19.62 KN/m2.
Ptotal = Patm + Poil.
Ptotal = 19.62 + 9.81 = 29.43 KN/m2.
P in-term of water = 29.43/9.81 = 3m of water.
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