Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 5)
5.
If the atmospheric pressure on the surface of an oil tank (sp. gr. 0.8) is 0.1 kg/cm2, the pressure at a depth of 2.5 m, is
Discussion:
42 comments Page 4 of 5.
Bhoj said:
3 years ago
0.1kg/cm^2 = 1m,
Pressure of 5m water = pressure of 5m* sp.gravity,
Or, = 2.5 * 0.8,= 2
Therefore
(1+2)= 3m.
Pressure of 5m water = pressure of 5m* sp.gravity,
Or, = 2.5 * 0.8,= 2
Therefore
(1+2)= 3m.
(22)
Ccjayesh said:
10 years ago
Pa = 0.1 kg/cm2 = 1000 kg/m2.
Poil = 800*2.5 = 2000 kg/m2.
Total = 3000 kg/m2 = 3000/1000 = 3 meters of water.
Poil = 800*2.5 = 2000 kg/m2.
Total = 3000 kg/m2 = 3000/1000 = 3 meters of water.
Prashant said:
7 years ago
How (total pressure/atm pressure) is equal to the pressure head of water?
Please explain anyone.
Thanks.
Please explain anyone.
Thanks.
Saurabh kaday said:
5 years ago
Don't understand clearly.
Anyone, please solve it by standard formula with step by step with meaning.
Anyone, please solve it by standard formula with step by step with meaning.
Nikita patil said:
1 decade ago
How do you calculate the pressure at the given height? Please explain me.
Nikku said:
1 decade ago
Pressure head in terms of water = 2.5/0.8 = 3.1m.
(1)
Suresh yadav said:
8 years ago
Yes, your answer is correct. Thank you @Dipesh.
Hitesh kumar said:
1 decade ago
Total pressure = ((.1*10^4)/1000)+(.8*2.5) = 3.
Makar said:
8 years ago
1 kg/m2 = 1000kg/cm2 this are correct.
Gurmeet said:
8 years ago
Simply P = density * gh.
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