Civil Engineering - Hydraulics - Discussion

Discussion Forum : Hydraulics - Section 1 (Q.No. 12)
12.
Unit of kinematic viscosity is
m2/sec
Newton sec/m2
Newton sec/m3
Kg sec/m2.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Bhagwan said:   3 years ago
Kinemetic viscocity k = dynamic viscocity/density.
Dynamic viscocity = N-sec/m^2.
Density = kg/m^3.
Hence K = (N-sec/m^3)/(kg/m^3).
1N = Kg-m/s^2.
So, K = ((Kg-m/s^2)/m^3)/(kg/m^3).
K = m^2/s.
(3)

Abhisek said:   6 years ago
Kinametic viscocity k = dynamic viscocity/density.
Dynamic viscocity = N-sec/m^2.
Density = kg/m^3.
Hence K = (N-sec/m^3)/(kg/m^3).
1N = Kg-m/s^2.
So K = ((Kg-m/s^2)/m^3)/(kg/m^3).
K = m^2/s.
(1)

Nidhi hinal said:   1 decade ago
Unit of dynamic viscosity = Ns/m2.

Unit of density = kg/m3.

Now, kinetic viscosity = dynamic viscosity/density.
= (N sec/m2)/(kg/m3).
= (mass x gravity x sec/m2)/(kg/m3).
= (kg x m/sec2) x (sec/m2)/(kg/m3).
= m2/sec.

Utpal said:   10 years ago
Thank you, @Nidhi Hinal.

RAJA said:   9 years ago
Nice explanation @Nidhi Hinal.

Sachin said:   9 years ago
Nice explanation @Nidhi Hinal.

Era examiner said:   9 years ago
Thank you @Nidhi.

PARASHURAM KAGI said:   9 years ago
kinametic viscocity k = dynamic viscocity/density.
Dynamic viscocity = N-sec/m^2.
Density = m^3/sec.
Hence K= N-sec/m^3/m^3/sec.
k = N/m^2.

Mahesh bisen said:   9 years ago
Good explanation, thanks @ @Nidhi Hinal.

Rajkumar said:   7 years ago
Excellent explanations. Thanks All.

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