Civil Engineering - Hydraulics - Discussion

12. 

Unit of kinematic viscosity is

[A]. m2/sec
[B]. Newton sec/m2
[C]. Newton sec/m3
[D]. Kg sec/m2.

Answer: Option A

Explanation:

No answer description available for this question.

Nidhi Hinal said: (Nov 1, 2013)  
Unit of dynamic viscosity = Ns/m2.

Unit of density = kg/m3.

Now, kinetic viscosity = dynamic viscosity/density.
= (N sec/m2)/(kg/m3).
= (mass x gravity x sec/m2)/(kg/m3).
= (kg x m/sec2) x (sec/m2)/(kg/m3).
= m2/sec.

Utpal said: (Mar 29, 2016)  
Thank you, @Nidhi Hinal.

Raja said: (Jun 30, 2016)  
Nice explanation @Nidhi Hinal.

Sachin said: (Sep 17, 2016)  
Nice explanation @Nidhi Hinal.

Era Examiner said: (Oct 2, 2016)  
Thank you @Nidhi.

Parashuram Kagi said: (Oct 7, 2016)  
kinametic viscocity k = dynamic viscocity/density.
Dynamic viscocity = N-sec/m^2.
Density = m^3/sec.
Hence K= N-sec/m^3/m^3/sec.
k = N/m^2.

Mahesh Bisen said: (Nov 7, 2016)  
Good explanation, thanks @ @Nidhi Hinal.

Rajkumar said: (May 17, 2018)  
Excellent explanations. Thanks All.

Abhisek said: (Nov 6, 2019)  
Kinametic viscocity k = dynamic viscocity/density.
Dynamic viscocity = N-sec/m^2.
Density = kg/m^3.
Hence K = (N-sec/m^3)/(kg/m^3).
1N = Kg-m/s^2.
So K = ((Kg-m/s^2)/m^3)/(kg/m^3).
K = m^2/s.

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