# Civil Engineering - Hydraulics - Discussion

### Discussion :: Hydraulics - Section 1 (Q.No.12)

12.

Unit of kinematic viscosity is

 [A]. m2/sec [B]. Newton sec/m2 [C]. Newton sec/m3 [D]. Kg sec/m2.

Explanation:

No answer description available for this question.

 Nidhi Hinal said: (Nov 1, 2013) Unit of dynamic viscosity = Ns/m2. Unit of density = kg/m3. Now, kinetic viscosity = dynamic viscosity/density. = (N sec/m2)/(kg/m3). = (mass x gravity x sec/m2)/(kg/m3). = (kg x m/sec2) x (sec/m2)/(kg/m3). = m2/sec.

 Utpal said: (Mar 29, 2016) Thank you, @Nidhi Hinal.

 Raja said: (Jun 30, 2016) Nice explanation @Nidhi Hinal.

 Sachin said: (Sep 17, 2016) Nice explanation @Nidhi Hinal.

 Era Examiner said: (Oct 2, 2016) Thank you @Nidhi.

 Parashuram Kagi said: (Oct 7, 2016) kinametic viscocity k = dynamic viscocity/density. Dynamic viscocity = N-sec/m^2. Density = m^3/sec. Hence K= N-sec/m^3/m^3/sec. k = N/m^2.

 Mahesh Bisen said: (Nov 7, 2016) Good explanation, thanks @ @Nidhi Hinal.

 Rajkumar said: (May 17, 2018) Excellent explanations. Thanks All.

 Abhisek said: (Nov 6, 2019) Kinametic viscocity k = dynamic viscocity/density. Dynamic viscocity = N-sec/m^2. Density = kg/m^3. Hence K = (N-sec/m^3)/(kg/m^3). 1N = Kg-m/s^2. So K = ((Kg-m/s^2)/m^3)/(kg/m^3). K = m^2/s.