Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 3 (Q.No. 47)
47.
If V is the design speed in km/hour and R is the radius of the curve of a hill road, the super-elevation
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Muhammad Hashim said:   3 years ago
On hills, the max value of super elevation is adopted which is v2/225R.
(2)

Seeker said:   5 years ago
e+f = v2/127R.
e= v2/225R ( if you ignore friction then take 0.75 of design speed as speed).
(1)

Negash said:   6 years ago
B is correct because v is design speed(0.75v).

Killo pradeep said:   7 years ago
I think B is the answer that formula itself used for V in kmph.

Aadarsh said:   7 years ago
For Kmph, the answer is C.
(1)

Ravi said:   7 years ago
I think B is the correct answer.

Pradeep chauhan said:   7 years ago
It is V^2/127R.

Garry said:   8 years ago
As per IRC 52, the correct answer is C.

Anuj nehra said:   8 years ago
C is the correct answer as e+u=V^2/(127R) but if we calculate e only without the coefficient of friction formula is e=(0.75V)2/(127R) ie V^2/(225R).
(1)

Suman koirala said:   1 decade ago
The Correct answer is options B i.e. e = v^2/(127R).
(1)

Post your comments here:

Your comments will be displayed after verification.