Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 2 (Q.No. 5)
5.
In an ideal transition curve, the radius of curvature
Discussion:
9 comments Page 1 of 1.
Venky said:
1 decade ago
L = v^2/r or 2.7(v^2/R).
(1)
Vikash said:
9 years ago
As ,Ls = v^3/CR.
Madhu said:
8 years ago
Radius of the transition curve is 0 at the tangent point and infinity at the starting of the circular curve. So it is varying through out its length. So the option should be B. In the question, it is stated radius of curvature not the length of the curve. So the above formula is not applicable here @Vikash.
Silent said:
6 years ago
Its answer should be D.
Because:
Ls is inversely prop.to Rc (transition).
also, Ls = V^2 / R or V^3/CR.
Because:
Ls is inversely prop.to Rc (transition).
also, Ls = V^2 / R or V^3/CR.
Samiran said:
6 years ago
If it's length then the option C is correct.
Dipuunku said:
5 years ago
Good explanation. Thanks @Madhu.
Ajay Sharma said:
5 years ago
But it is mentioned that it is the ideal transition curve. The shape of ideal transition curve is spiral. So C is correct.
Najaf said:
4 years ago
Clothiod & spiral same thing. L is inverse relations with radius.
Biki said:
2 years ago
Ls = v^3/47CR.
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