Civil Engineering - Highway Engineering - Discussion

5. 

In an ideal transition curve, the radius of curvature

[A]. is constant
[B]. at any point is directly proportional to its distance from the point of commencement
[C]. is inversely proportional to the radius of main curve
[D]. is directly proportional to the radius of main curve

Answer: Option C

Explanation:

No answer description available for this question.

Venky said: (Sep 10, 2013)  
L = v^2/r or 2.7(v^2/R).

Vikash said: (Jul 15, 2016)  
As ,Ls = v^3/CR.

Madhu said: (Dec 25, 2017)  
Radius of the transition curve is 0 at the tangent point and infinity at the starting of the circular curve. So it is varying through out its length. So the option should be B. In the question, it is stated radius of curvature not the length of the curve. So the above formula is not applicable here @Vikash.

Silent said: (Feb 6, 2020)  
Its answer should be D.

Because:
Ls is inversely prop.to Rc (transition).
also, Ls = V^2 / R or V^3/CR.

Samiran said: (Feb 10, 2020)  
If it's length then the option C is correct.

Dipuunku said: (Aug 28, 2020)  
Good explanation. Thanks @Madhu.

Ajay Sharma said: (Jan 27, 2021)  
But it is mentioned that it is the ideal transition curve. The shape of ideal transition curve is spiral. So C is correct.

Najaf said: (Aug 22, 2021)  
Clothiod & spiral same thing. L is inverse relations with radius.

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