Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 2 (Q.No. 5)
5.
In an ideal transition curve, the radius of curvature
is constant
at any point is directly proportional to its distance from the point of commencement
is inversely proportional to the radius of main curve
is directly proportional to the radius of main curve
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
9 comments Page 1 of 1.

Biki said:   8 months ago
Ls = v^3/47CR.

Najaf said:   3 years ago
Clothiod & spiral same thing. L is inverse relations with radius.

Ajay Sharma said:   3 years ago
But it is mentioned that it is the ideal transition curve. The shape of ideal transition curve is spiral. So C is correct.

Dipuunku said:   4 years ago
Good explanation. Thanks @Madhu.

Samiran said:   4 years ago
If it's length then the option C is correct.

Silent said:   4 years ago
Its answer should be D.

Because:
Ls is inversely prop.to Rc (transition).
also, Ls = V^2 / R or V^3/CR.

Madhu said:   6 years ago
Radius of the transition curve is 0 at the tangent point and infinity at the starting of the circular curve. So it is varying through out its length. So the option should be B. In the question, it is stated radius of curvature not the length of the curve. So the above formula is not applicable here @Vikash.

Vikash said:   8 years ago
As ,Ls = v^3/CR.

Venky said:   1 decade ago
L = v^2/r or 2.7(v^2/R).

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