Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 2 (Q.No. 4)
4.
If x% is the gradient of an alignment and y% is the gradient after proper superelevation along a curved portion of a highway, the differential grade along the curve, is
Discussion:
8 comments Page 1 of 1.
Samm said:
9 years ago
Why not (x-y) %? Please explain.
(1)
Ng reddy said:
9 years ago
That is called grade compensation.
At the time of horizontal curves, we reduce the gradient 75/r or (30 + r) /r.
At the time of horizontal curves, we reduce the gradient 75/r or (30 + r) /r.
(1)
BB Bande said:
8 years ago
Please explain this.
(1)
Anom said:
7 years ago
How the gradient is increased after attaining super elevation?
Please suggest.
Please suggest.
(1)
Hira said:
5 years ago
The grade is decreased in a curve, not increased. It is called grade compensation. Y-X % is differential grade. Although, y% is lesser or flatter than x%.
(1)
Andal said:
9 years ago
The normal gradient ( slope of the ground ) is x% which is the same value at the point of Transition curve. The super elevation is starting from this Transition point and ending at the mid of curvature of the horizontal curve.
Hence, after super elevation attained, the difference between gradient is (y-x)%.
Hence, after super elevation attained, the difference between gradient is (y-x)%.
Garry said:
8 years ago
The Answer is correct because Y% is the gradient after attaining full superelevation.
Previously it has X%. So the difference will be {Y-X}%.
Previously it has X%. So the difference will be {Y-X}%.
Ankush said:
8 years ago
y-x is the right answer.
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