Civil Engineering - Highway Engineering - Discussion


If x% is the gradient of an alignment and y% is the gradient after proper superelevation along a curved portion of a highway, the differential grade along the curve, is

[A]. (x + y)%
[B]. (x - y)%
[C]. (y - x)%
[D]. (x x y)%
[E]. (y + x)%

Answer: Option C


No answer description available for this question.

Samm said: (Aug 6, 2016)  
Why not (x-y) %? Please explain.

Ng Reddy said: (Sep 27, 2016)  
That is called grade compensation.

At the time of horizontal curves, we reduce the gradient 75/r or (30 + r) /r.

Andal said: (Jan 10, 2017)  
The normal gradient ( slope of the ground ) is x% which is the same value at the point of Transition curve. The super elevation is starting from this Transition point and ending at the mid of curvature of the horizontal curve.

Hence, after super elevation attained, the difference between gradient is (y-x)%.

Bb Bande said: (Aug 28, 2017)  
Please explain this.

Garry said: (Jan 20, 2018)  
The Answer is correct because Y% is the gradient after attaining full superelevation.

Previously it has X%. So the difference will be {Y-X}%.

Ankush said: (Feb 16, 2018)  
y-x is the right answer.

Anom said: (Mar 25, 2018)  
How the gradient is increased after attaining super elevation?

Please suggest.

Hira said: (Dec 4, 2020)  
The grade is decreased in a curve, not increased. It is called grade compensation. Y-X % is differential grade. Although, y% is lesser or flatter than x%.

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