Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 1 (Q.No. 12)
12.
Pick up the incorrect statement from the following. The super-elevation on roads is
directly proportional to width of pavement
directly proportional to velocity of vehicles
inversely proportional to acceleration due to gravity
inversely proportional to the radius of curvature.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
56 comments Page 4 of 6.

Sagar Shah said:   1 decade ago
Is it they are considering directly proportional to square of velocity?

Srikanth IIITBasar said:   1 decade ago
Actually it is not directly proportional to width of pavement. Because,

Superelevation (e) = tan (tita) = sin (tita) = opp side /hyp= E/ width of pavement.

Joce said:   1 decade ago
It is directly proportional to the velocity square and inversely proportional to the radius of curvature.

TANMOY SAHA said:   1 decade ago
Superelevation(E) = Rate of superelevation(e)* Width of pavement(B).

So E directly proportional to B,
So the correct option will be 'B' .

Pawan said:   1 decade ago
Equation e + f = v2/127 R.

Thus e directly proportional to velocity and inversely proportional to radius of curvature which
is right.

So incorrect answer is option C inversely proportional to acceleration due to gravity.

Bcr said:   1 decade ago
e+f=(v*v)/gR
So directly prop to v.

Indirectly prop to radius and gravity.
Hence option A would be the answer.

Bharathi said:   1 decade ago
Super elevation is directly proportional to the square of the velocity and inversely proportional to the acceleration due to gravity, radius of the curvature.

Prasanna said:   1 decade ago
I think answer should be option (a), because question asking for incorrect statement.

PADMINI said:   1 decade ago
e = WV^2/gR.
V^2 is direct proportional.

Sabariii said:   10 years ago
No @Mr. Prasanna,

Total super elevation = e*W.

Where e - rate of SE.

W - Width of pavement.


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