Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 12)
12.
Pick up the incorrect statement from the following. The super-elevation on roads is
Discussion:
56 comments Page 3 of 6.
SANTOSH kumar said:
7 years ago
e=V2/gr.
So, I think all option is true. But, e is directly proportional to the square of the velocity of the vehicle.
So, I think all option is true. But, e is directly proportional to the square of the velocity of the vehicle.
Swar said:
7 years ago
e=tan (θ) = opp/adj = h/b = central rise/width.
So super elevation is inversely proportional to width of pavement. But they have given as directly prop. So the answer is A.
So super elevation is inversely proportional to width of pavement. But they have given as directly prop. So the answer is A.
ANJAN said:
6 years ago
e+f = (0.278V)'2/9.8R.
So, option A is correct.
So, option A is correct.
Pari.. said:
6 years ago
Super elevation is inversely proportional to the radius.
E!=e B where e is the super-elevation.
E!=e B where e is the super-elevation.
JP Mahanta said:
6 years ago
Super elevation doesn't depends on road width, The E value (height of outer edge of road at super-elevation) depends upon e (rate of super-elevation).
Benjifanai said:
5 years ago
Guys. Question is actually trick you. B is Right.
E=eB.
e=v*v/gR.
SO,
E=v*v*B/gR.
From the final equation.
E directly proportion to width, the square of the velocity and, inversely proportional to the g and R.
here, superelevation does not directly proportional to the velocity of vehicles, but the only square of the velocity.
SO, answer B IS RIGHT.
E=eB.
e=v*v/gR.
SO,
E=v*v*B/gR.
From the final equation.
E directly proportion to width, the square of the velocity and, inversely proportional to the g and R.
here, superelevation does not directly proportional to the velocity of vehicles, but the only square of the velocity.
SO, answer B IS RIGHT.
Anomie said:
5 years ago
e=v^2/Rg so directly proportional to the square of thè velocity.
Shiw Sanku shaw said:
5 years ago
How?
Dinesh Sinha said:
4 years ago
Option A will be the answer.
Because, super elevation (e) = tan(theta)= Tangent/Base.
So, if base ie. The width will increase then Tangent ie. The rise of the outer edge will be increased to maintain as tan (theta). After that theta (angle of inclination) will be the same.
So, e= tan theta dependable on theta and not dependable on the width
Because, super elevation (e) = tan(theta)= Tangent/Base.
So, if base ie. The width will increase then Tangent ie. The rise of the outer edge will be increased to maintain as tan (theta). After that theta (angle of inclination) will be the same.
So, e= tan theta dependable on theta and not dependable on the width
Subeer kumar said:
9 years ago
Superelevation is directly proportional to velocity of the vehicle because for particular curve on the road radius of curve remains constant for that curve.
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