Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 12)
12.
Pick up the incorrect statement from the following. The super-elevation on roads is
Discussion:
57 comments Page 3 of 6.
Kshitij mishra said:
9 years ago
As super elevation e+f=v^2/ (g.r) so it is directly proportional to the design speed option b is incorrect because the speed of vehicles is mentioned there in the statement not the design speed of the vehicle will differ for the different vehicle so it is incorrect.
Because s.e can be made on design speed.
Because s.e can be made on design speed.
Vijay rajput said:
8 years ago
Super elevation =V*2/gR=F/W<=b/2h.
So, the answer is b.
So, the answer is b.
Rudresh meena said:
8 years ago
A is correct because velocity of vehicle is directly proportional to super elevation.
Rudresh meena said:
8 years ago
A is correct because velocity of vehicle is directly proportional to super elevation.
Rudresh meena said:
8 years ago
A is correct because velocity of vehicle is directly proportional to super elevation.
Shiw Sanku shaw said:
6 years ago
How?
Swar said:
8 years ago
e=tan (θ) = opp/adj = h/b = central rise/width.
So super elevation is inversely proportional to width of pavement. But they have given as directly prop. So the answer is A.
So super elevation is inversely proportional to width of pavement. But they have given as directly prop. So the answer is A.
Pari.. said:
7 years ago
Super elevation is inversely proportional to the radius.
E!=e B where e is the super-elevation.
E!=e B where e is the super-elevation.
Benjifanai said:
6 years ago
Guys. Question is actually trick you. B is Right.
E=eB.
e=v*v/gR.
SO,
E=v*v*B/gR.
From the final equation.
E directly proportion to width, the square of the velocity and, inversely proportional to the g and R.
here, superelevation does not directly proportional to the velocity of vehicles, but the only square of the velocity.
SO, answer B IS RIGHT.
E=eB.
e=v*v/gR.
SO,
E=v*v*B/gR.
From the final equation.
E directly proportion to width, the square of the velocity and, inversely proportional to the g and R.
here, superelevation does not directly proportional to the velocity of vehicles, but the only square of the velocity.
SO, answer B IS RIGHT.
Anomie said:
6 years ago
e=v^2/Rg so directly proportional to the square of thè velocity.
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