Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 1 (Q.No. 12)
12.
Pick up the incorrect statement from the following. The super-elevation on roads is
directly proportional to width of pavement
directly proportional to velocity of vehicles
inversely proportional to acceleration due to gravity
inversely proportional to the radius of curvature.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
56 comments Page 5 of 6.

Bhagchad Golhani said:   9 years ago
e is directly proportional to v^2 and also inversely proportional to R.

Snehal said:   9 years ago
e is the rate of superelevation.

h = e * B is the super elevation (which is proportional to width).

Pakeeza Jhan said:   9 years ago
Super-elevation = v^2/2r.

Hence, it should be directly proportional to square root of velocity and inversely proportional to the radius of curvature.

Priya said:   1 decade ago
Directly proportional to the velocity and also inversely proportional to the radius of curvature.

Dambar said:   9 years ago
Total super elevation E= e * W.

Lucky jaswal said:   9 years ago
directly proportional to velocity and width.
Inversely to the radius.

It seems wrong in acceleration.

Pramit said:   9 years ago
According to me, It's directly proportional to the SQUARE of velocity.

Engr asad said:   8 years ago
W V^2
_____
gr

Directly proportional = width and sq of speed (not velocity).
Inversely = acceleration due to gravity and radius of the curve.

Lone Khursheed said:   8 years ago
E = eB.
Here in above relation;
e= Rate of super elevation,
And E = total super elevation.

Therefore total super elevation is directly proportional to width B.
But rate of super-elevation that is e is not proportional to width as the product of e and B is equal to E.

So, option A is incorrect.

Bikash Kabiraj said:   8 years ago
V^2/gr.

v-velocity of the vehicle,
g-gravitational force,
r-radius of the curve so right answer is option A.


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