Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 12)
12.
Pick up the incorrect statement from the following. The super-elevation on roads is
Discussion:
56 comments Page 4 of 6.
Amit said:
8 years ago
The correct answer is A.
SABIN ACHARYA said:
8 years ago
E=eB.
e=v*v/gR.
SO,
E=v*v*B/gR.
From final equation.
E directly proportion to width, square of velocity and,
inversely proportional to the g and R.
SO, ans B IS RIGHT.
e=v*v/gR.
SO,
E=v*v*B/gR.
From final equation.
E directly proportion to width, square of velocity and,
inversely proportional to the g and R.
SO, ans B IS RIGHT.
Bicky agarwal said:
8 years ago
Here, e+f=v^2/gR.
So, A will be answer.
So, A will be answer.
Sameer naik said:
8 years ago
1) e=E/w.
2) e+f=v^2/gR.
Answer A is exactaly correct.
2) e+f=v^2/gR.
Answer A is exactaly correct.
Surya said:
8 years ago
I think option A is the correct answer.
Bikash Kabiraj said:
8 years ago
V^2/gr.
v-velocity of the vehicle,
g-gravitational force,
r-radius of the curve so right answer is option A.
v-velocity of the vehicle,
g-gravitational force,
r-radius of the curve so right answer is option A.
Lone Khursheed said:
8 years ago
E = eB.
Here in above relation;
e= Rate of super elevation,
And E = total super elevation.
Therefore total super elevation is directly proportional to width B.
But rate of super-elevation that is e is not proportional to width as the product of e and B is equal to E.
So, option A is incorrect.
Here in above relation;
e= Rate of super elevation,
And E = total super elevation.
Therefore total super elevation is directly proportional to width B.
But rate of super-elevation that is e is not proportional to width as the product of e and B is equal to E.
So, option A is incorrect.
Engr asad said:
8 years ago
W V^2
_____
gr
Directly proportional = width and sq of speed (not velocity).
Inversely = acceleration due to gravity and radius of the curve.
_____
gr
Directly proportional = width and sq of speed (not velocity).
Inversely = acceleration due to gravity and radius of the curve.
Pramit said:
9 years ago
According to me, It's directly proportional to the SQUARE of velocity.
Lucky jaswal said:
9 years ago
directly proportional to velocity and width.
Inversely to the radius.
It seems wrong in acceleration.
Inversely to the radius.
It seems wrong in acceleration.
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