Civil Engineering - Highway Engineering - Discussion

A is correct because velocity of vehicle is directly proportional to super elevation.

A is correct because velocity of vehicle is directly proportional to super elevation.

Super elevation =V*2/gR=F/W<=b/2h.
So, the answer is b.

As super elevation e+f=v^2/ (g.r) so it is directly proportional to the design speed option b is incorrect because the speed of vehicles is mentioned there in the statement not the design speed of the vehicle will differ for the different vehicle so it is incorrect.

Because s.e can be made on design speed.

e=v2/gR,

So answer A is correct because question is asking incorrect statement, but superelevation is directly proportional to the square of velocity and inversely proportional to acceleration due to gravity and radius of curvature.

Please, anyone explain me how's answer B?

Actually, incorrect answer is opt A because when the width is extra large we need not provide super elevation and when the width is narrow we should increase super elevation to provide safe passage of vehicles.

Basically super elevation is provided to counter the centrifugal force and to reduce the tendency of fast moving vehicles to overturn. If super elevation is less or zero vehicles will have to reduce their speeds to safely turn it. Hence answer B is correct.

I think opt A is the actual incorrect statement. Because from the formulae E= e (rate of super elevation) * B (width of pavement) for designing super elevation, for a perticular pavement width B is same but rate of superelevation can be changed. So width is not proportional to value of superelevation (E). Again superelevation is provided for counteract centrifugal force which is ev^2/gR. So opt C is correct statement. So. Who answered opt A I will go with them.

A is the right answer.