Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 12)
12.
Pick up the incorrect statement from the following. The super-elevation on roads is
Discussion:
56 comments Page 2 of 6.
Anomie said:
5 years ago
e=v^2/Rg so directly proportional to the square of thè velocity.
Benjifanai said:
5 years ago
Guys. Question is actually trick you. B is Right.
E=eB.
e=v*v/gR.
SO,
E=v*v*B/gR.
From the final equation.
E directly proportion to width, the square of the velocity and, inversely proportional to the g and R.
here, superelevation does not directly proportional to the velocity of vehicles, but the only square of the velocity.
SO, answer B IS RIGHT.
E=eB.
e=v*v/gR.
SO,
E=v*v*B/gR.
From the final equation.
E directly proportion to width, the square of the velocity and, inversely proportional to the g and R.
here, superelevation does not directly proportional to the velocity of vehicles, but the only square of the velocity.
SO, answer B IS RIGHT.
JP Mahanta said:
6 years ago
Super elevation doesn't depends on road width, The E value (height of outer edge of road at super-elevation) depends upon e (rate of super-elevation).
Pari.. said:
6 years ago
Super elevation is inversely proportional to the radius.
E!=e B where e is the super-elevation.
E!=e B where e is the super-elevation.
ANJAN said:
6 years ago
e+f = (0.278V)'2/9.8R.
So, option A is correct.
So, option A is correct.
Pratibha Nishad said:
7 years ago
Directly proportional to the velocity and also inversely proportional to the radius of curvature.
(1)
Swar said:
7 years ago
e=tan (θ) = opp/adj = h/b = central rise/width.
So super elevation is inversely proportional to width of pavement. But they have given as directly prop. So the answer is A.
So super elevation is inversely proportional to width of pavement. But they have given as directly prop. So the answer is A.
Utsav said:
7 years ago
Directly proportional to velocity square I guess that's why it's incorrect here!
(1)
SANTOSH kumar said:
7 years ago
e=V2/gr.
So, I think all option is true. But, e is directly proportional to the square of the velocity of the vehicle.
So, I think all option is true. But, e is directly proportional to the square of the velocity of the vehicle.
Rudresh meena said:
7 years ago
A is correct because velocity of vehicle is directly proportional to super elevation.
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