Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 12)
12.
Pick up the incorrect statement from the following. The super-elevation on roads is
Discussion:
57 comments Page 5 of 6.
Lucky jaswal said:
9 years ago
directly proportional to velocity and width.
Inversely to the radius.
It seems wrong in acceleration.
Inversely to the radius.
It seems wrong in acceleration.
Dambar said:
9 years ago
Total super elevation E= e * W.
Subeer kumar said:
9 years ago
Superelevation is directly proportional to velocity of the vehicle because for particular curve on the road radius of curve remains constant for that curve.
Pakeeza Jhan said:
9 years ago
Super-elevation = v^2/2r.
Hence, it should be directly proportional to square root of velocity and inversely proportional to the radius of curvature.
Hence, it should be directly proportional to square root of velocity and inversely proportional to the radius of curvature.
Snehal said:
9 years ago
e is the rate of superelevation.
h = e * B is the super elevation (which is proportional to width).
h = e * B is the super elevation (which is proportional to width).
Bhagchad Golhani said:
10 years ago
e is directly proportional to v^2 and also inversely proportional to R.
Sabariii said:
1 decade ago
No @Mr. Prasanna,
Total super elevation = e*W.
Where e - rate of SE.
W - Width of pavement.
Total super elevation = e*W.
Where e - rate of SE.
W - Width of pavement.
PADMINI said:
1 decade ago
e = WV^2/gR.
V^2 is direct proportional.
V^2 is direct proportional.
Prasanna said:
1 decade ago
I think answer should be option (a), because question asking for incorrect statement.
Bharathi said:
1 decade ago
Super elevation is directly proportional to the square of the velocity and inversely proportional to the acceleration due to gravity, radius of the curvature.
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