Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 4 (Q.No. 2)
2.
For a comfortable travel on Highways, the centrifugal ratio should not exceed
Discussion:
13 comments Page 1 of 2.
Anirban Roy said:
5 years ago
Max centrifugal ratio:
For highways = 1/4.
For railways = 1/8.
For highways = 1/4.
For railways = 1/8.
(4)
Anirban Roy said:
5 years ago
We know, for superelevation:
e+f= v^2/gR. The term on the RHS of the equal sign is called the centrifugal ratio.
We know maximum values of:
e= 0.07 and f= 0.15.
So, (e+f )max= 0.22.
e+f= v^2/gR. The term on the RHS of the equal sign is called the centrifugal ratio.
We know maximum values of:
e= 0.07 and f= 0.15.
So, (e+f )max= 0.22.
(3)
Rons baba said:
5 years ago
Thanks @Piyush Singh.
(1)
Reddy said:
6 years ago
But it should not exceed lateral friction (.15), considering lateral skidding at curves.
Vikram Gupta said:
6 years ago
What is the significance of the impact factor/centrifugal ratio?
Umang said:
6 years ago
Thank you all for explaining it.
Swar said:
7 years ago
Thanks @Piyush and @Narasimha.
Narasimha said:
7 years ago
Centrifugal force P = MV^2/R,
We know W = Mg, P/W = V^2/R.
Where, P/W is called centrifugal ratio or impact factor.
We know W = Mg, P/W = V^2/R.
Where, P/W is called centrifugal ratio or impact factor.
Sushant chaturvedi said:
7 years ago
Can anyone explain this centrifugal ratio?
Anomi said:
7 years ago
Thanks for the answer.
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