Civil Engineering - Highway Engineering - Discussion

2. 

For a comfortable travel on Highways, the centrifugal ratio should not exceed

[A]. 0.10
[B]. 0.15
[C]. 0.20
[D]. 0.25
[E]. 0.30

Answer: Option D

Explanation:

No answer description available for this question.

Piyush Singh said: (May 21, 2015)  
For Highways centrifugal ratio (v^2/gr) = 1/4 = 0.25.

Maximum superelevation should be 1/4 for comfortable ride.

For Railways Centrifugal ratio should be 1/8 = 0.125.

Chhaya said: (May 2, 2017)  
Thanks @Piyush Singh.

Ashu said: (Nov 22, 2017)  
Thanks @Piyush.

Anomi said: (Aug 25, 2018)  
Thanks for the answer.

Sushant Chaturvedi said: (Nov 2, 2018)  
Can anyone explain this centrifugal ratio?

Narasimha said: (Nov 21, 2018)  
Centrifugal force P = MV^2/R,
We know W = Mg, P/W = V^2/R.
Where, P/W is called centrifugal ratio or impact factor.

Swar said: (Jan 10, 2019)  
Thanks @Piyush and @Narasimha.

Umang said: (Jun 15, 2019)  
Thank you all for explaining it.

Vikram Gupta said: (Jul 21, 2019)  
What is the significance of the impact factor/centrifugal ratio?

Reddy said: (Feb 5, 2020)  
But it should not exceed lateral friction (.15), considering lateral skidding at curves.

Rons Baba said: (Mar 21, 2020)  
Thanks @Piyush Singh.

Anirban Roy said: (Aug 26, 2020)  
We know, for superelevation:

e+f= v^2/gR. The term on the RHS of the equal sign is called the centrifugal ratio.

We know maximum values of:
e= 0.07 and f= 0.15.
So, (e+f )max= 0.22.

Anirban Roy said: (Aug 26, 2020)  
Max centrifugal ratio:
For highways = 1/4.
For railways = 1/8.

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