### Discussion :: Highway Engineering - Section 4 (Q.No.2)

Piyush Singh said: (May 21, 2015) | |

For Highways centrifugal ratio (v^2/gr) = 1/4 = 0.25. Maximum superelevation should be 1/4 for comfortable ride. For Railways Centrifugal ratio should be 1/8 = 0.125. |

Chhaya said: (May 2, 2017) | |

Thanks @Piyush Singh. |

Ashu said: (Nov 22, 2017) | |

Thanks @Piyush. |

Anomi said: (Aug 25, 2018) | |

Thanks for the answer. |

Sushant Chaturvedi said: (Nov 2, 2018) | |

Can anyone explain this centrifugal ratio? |

Narasimha said: (Nov 21, 2018) | |

Centrifugal force P = MV^2/R, We know W = Mg, P/W = V^2/R. Where, P/W is called centrifugal ratio or impact factor. |

Swar said: (Jan 10, 2019) | |

Thanks @Piyush and @Narasimha. |

Umang said: (Jun 15, 2019) | |

Thank you all for explaining it. |

Vikram Gupta said: (Jul 21, 2019) | |

What is the significance of the impact factor/centrifugal ratio? |

Reddy said: (Feb 5, 2020) | |

But it should not exceed lateral friction (.15), considering lateral skidding at curves. |

Rons Baba said: (Mar 21, 2020) | |

Thanks @Piyush Singh. |

Anirban Roy said: (Aug 26, 2020) | |

We know, for superelevation: e+f= v^2/gR. The term on the RHS of the equal sign is called the centrifugal ratio. We know maximum values of: e= 0.07 and f= 0.15. So, (e+f )max= 0.22. |

Anirban Roy said: (Aug 26, 2020) | |

Max centrifugal ratio: For highways = 1/4. For railways = 1/8. |

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