Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 4 (Q.No. 2)
For a comfortable travel on Highways, the centrifugal ratio should not exceed
Answer: Option
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13 comments Page 1 of 2.

Anirban Roy said:   4 years ago
Max centrifugal ratio:
For highways = 1/4.
For railways = 1/8.

Anirban Roy said:   4 years ago
We know, for superelevation:

e+f= v^2/gR. The term on the RHS of the equal sign is called the centrifugal ratio.

We know maximum values of:
e= 0.07 and f= 0.15.
So, (e+f )max= 0.22.

Rons baba said:   4 years ago
Thanks @Piyush Singh.

Reddy said:   4 years ago
But it should not exceed lateral friction (.15), considering lateral skidding at curves.

Vikram Gupta said:   5 years ago
What is the significance of the impact factor/centrifugal ratio?

Umang said:   5 years ago
Thank you all for explaining it.

Swar said:   5 years ago
Thanks @Piyush and @Narasimha.

Narasimha said:   5 years ago
Centrifugal force P = MV^2/R,
We know W = Mg, P/W = V^2/R.
Where, P/W is called centrifugal ratio or impact factor.

Sushant chaturvedi said:   5 years ago
Can anyone explain this centrifugal ratio?

Anomi said:   6 years ago
Thanks for the answer.

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