Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 6 (Q.No. 43)
43.
If the difference in elevation of an edge of the pavement 9 m wide and its crown is 15 cm, the camber of the pavement, is
Discussion:
18 comments Page 2 of 2.
Utsav said:
7 years ago
A simple way is 450/15 = 30.
Hence 1 in 30.
Hence 1 in 30.
Roy said:
7 years ago
Thanks @Dabhi Deepak.
Prabhudas Mahapatra said:
7 years ago
Ymax = W/2N.
So, N = W/2 Ymax.
N= 900/2*15 = 30.
Gradient, G = 1 in N,
G = 1 in 30.
So, N = W/2 Ymax.
N= 900/2*15 = 30.
Gradient, G = 1 in N,
G = 1 in 30.
OSMAN said:
7 years ago
Camber is given on half-width of the road.
So, 9m/2=4.5m. Or 450cm.
Now given that,
For 450 cm long there is 15 cm height.
1 cm --- 15/450 = 1/30 or 1 in 30 =>answer.
So, 9m/2=4.5m. Or 450cm.
Now given that,
For 450 cm long there is 15 cm height.
1 cm --- 15/450 = 1/30 or 1 in 30 =>answer.
Mayur said:
7 years ago
The equation of straight camber:-
y= W/2N.
W - width of the road,
N - slope, y- ht of camber(crown),
0.15=9/2N,
N=9/2*0.15,
N= 30. So camber is 1 in 30.
y= W/2N.
W - width of the road,
N - slope, y- ht of camber(crown),
0.15=9/2N,
N=9/2*0.15,
N= 30. So camber is 1 in 30.
Pritesh Dabhade said:
8 years ago
Total width of carrige way = 9m.
So camber always consider distance from crown to edge which is 4.5m here.
Hence 4.5 ÷ 0.15 = 30,
So camber is 1 in 30.
So camber always consider distance from crown to edge which is 4.5m here.
Hence 4.5 ÷ 0.15 = 30,
So camber is 1 in 30.
Dabhi Deepak said:
9 years ago
It's so easy. Simple calculation.
Total pavement= 9m half = 9 * 0.5 = 4.5.
Horizontal Distance ------------- Vertical Distance.
4.5m. --------------> 0.15m.
1 m. -------------->?
0.15 / 4.5. = 1/30. Means 1 in 30.
Total pavement= 9m half = 9 * 0.5 = 4.5.
Horizontal Distance ------------- Vertical Distance.
4.5m. --------------> 0.15m.
1 m. -------------->?
0.15 / 4.5. = 1/30. Means 1 in 30.
Ashu said:
9 years ago
Please explain how it can be solved.
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