Discussion :: GATE Exam Questions - Section 4 (Q.No.17)
|Unknown said: (May 6, 2017)|
|Answer is (A): 10,000.
Explanation: Given: Modified length=9 cm, actual length=10 cm, actual relative factor=1/1000, modified area= 81 cm2, actual area=?
We know, Modified area= (modified relative factor/Actual relative factor)2*Actual area.
Actual area= Modified area/[(modified relative factor/Actual relative factor)2].
Actual area= 81/[(modified relative factor/1/1000)2].
Now, Modified length = (Modified RF/actual RF)*actual length.
9 cm = (Modified RF/1/1000) * 10.
Modified RF = 1/1111.11.
Actual area = 81/[(1/1111.11/1/1000)2]=99.99 = 100 cm.
As the actual scale is 1 cm to 10 m, hence.
Actual area = 100 * 102 = 10,000 m2.
|Shivaprasad Sajjan said: (Feb 20, 2019)|
|The scale of the original survey = 10m to 1cm.
The line originally 10cm measures 9cm.
Shrinkage factor = 9/10 = 0.9,
Reduced plan area = 81cm2.
Reduced plan area = shrinkage factor * actual plan area.
Actual plan area = 81/(0.9)^2 = 100cm2.
Actual area of survey=100*(10)^2 = 10000mts.
|Mahesh Sinh said: (May 22, 2020)|
|Good, thanks for explaining @Sajjan.|
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