# Civil Engineering - GATE Exam Questions - Discussion

### Discussion :: GATE Exam Questions - Section 4 (Q.No.4)

4.

Water emerges from an ogee spillway with velocity 13.72 m/s and depth = 3.0 m at its toe. The tail water depth required to form a hydraulic jump at the toe is

 [A]. 6.48 m [B]. 5.24 m [C]. 3.24 m [D]. 2.24 m

Explanation:

No answer description available for this question.

 RAKESH KUMAR said: (Jan 13, 2017) Can anyone explain this?

 Hitesh said: (Jan 9, 2018) Answer should be 9.8m as per calculation.

 Savy said: (Mar 15, 2018) 9.34 m is the answer.

 Noni said: (Sep 30, 2018) How do you calculate? Explain.

 Sangay Tenzin said: (Oct 2, 2018) I also got 9.334. y2/y1 = 1/2*(√(1+8.F1^2) - 1) y1 = depth of water before hydraulic jump y2 = depth of water after hydraulic jump F1 = froude number of flow before hydraulic jump i.e F=V/√(g*depth) = 13.72/(√(9.81*3)) = 2.52. y2 = 3* [1/2*( sqrt(1+8*2.52^2) - 1)]. y2 = 9.334m.

 DPR said: (Jan 25, 2021) Yes, you are right @SANGAY TENZIN. 9.334 m is the correct answer. The direct formula without getting frouds no is; y2/y1=0.5*(-1+{1+((8v1^2)/g*y)}^0.5).

 Jay Garachh said: (May 24, 2021) Put 0.3m instead of 3m you will get an answer.