Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 3 (Q.No. 32)
32.
The degree of static indeterminacy of the rigid frame having two internal hinges as shown in the figure below, is
Discussion:
10 comments Page 1 of 1.
Mumtaz Ali said:
5 years ago
Ds = Dsi + Dse = 4 + 1= 5.
(1)
Ajinkya said:
9 years ago
4 - 3 + 3 * 2 - 2 = 5.
Malatesh S Patil said:
8 years ago
@Ajinkya.
Can you please elaborate the answer?
Can you please elaborate the answer?
Poobathy said:
8 years ago
Dsi=4-3=1.
Dse=3*2=6.
Ds=1+6-2=5.
Dse=3*2=6.
Ds=1+6-2=5.
Sna said:
7 years ago
3 * 9 + 4 - 3 * 8 - 2 = 5.
Muhammad Zaid said:
7 years ago
(Total unkown)-(equilb eq).
(3m+r)-(3j+a).
a=factor use for internal hinge.
(3m+r)-(3j+a).
a=factor use for internal hinge.
Puja said:
7 years ago
In loop method, Dse=R-3. Where R is External Reaction..Dsi = 3*No of close loop - Additional condition of equilibrium (members-1).
Dse=3+1+1-3=1.
Dsi = 3 * 2-(m-1)-(m-1) = 6-(2-1)-(2-1)=4 .
Hinge is placed in between 2member so (m-1) is (2-1).
Dse=3+1+1-3=1.
Dsi = 3 * 2-(m-1)-(m-1) = 6-(2-1)-(2-1)=4 .
Hinge is placed in between 2member so (m-1) is (2-1).
Prenita said:
6 years ago
3*7 + 4-3 * 6-2 = 5.
Prenit said:
6 years ago
Thank you all for explaining.
Vikasgowda c j said:
5 years ago
Ds=Dse+Dsi.
Dse= no.Of reactions(r) - no.of equilibrium equn(s)
Dse= 4 - 3.
Dse= 1
Dsi= 3( no of closed-loop in a structure) -releases( when a hinge is present between members)
i.e, if the hinge is present between 2 members= m-1=2-1=1.
Dsi = 3C-1-1= 3(2)-2 = 6 - 2 = 4.
Ds = 1 + 4 = 5.
Dse= no.Of reactions(r) - no.of equilibrium equn(s)
Dse= 4 - 3.
Dse= 1
Dsi= 3( no of closed-loop in a structure) -releases( when a hinge is present between members)
i.e, if the hinge is present between 2 members= m-1=2-1=1.
Dsi = 3C-1-1= 3(2)-2 = 6 - 2 = 4.
Ds = 1 + 4 = 5.
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