Civil Engineering - GATE Exam Questions - Discussion

32. 

The degree of static indeterminacy of the rigid frame having two internal hinges as shown in the figure below, is

[A]. 8
[B]. 7
[C]. 6
[D]. 5

Answer: Option D

Explanation:

No answer description available for this question.

Ajinkya said: (Aug 15, 2016)  
4 - 3 + 3 * 2 - 2 = 5.

Malatesh S Patil said: (Jul 28, 2017)  
@Ajinkya.

Can you please elaborate the answer?

Poobathy said: (Sep 13, 2017)  
Dsi=4-3=1.
Dse=3*2=6.
Ds=1+6-2=5.

Sna said: (Sep 22, 2018)  
3 * 9 + 4 - 3 * 8 - 2 = 5.

Muhammad Zaid said: (Oct 4, 2018)  
(Total unkown)-(equilb eq).
(3m+r)-(3j+a).
a=factor use for internal hinge.

Puja said: (Jan 30, 2019)  
In loop method, Dse=R-3. Where R is External Reaction..Dsi = 3*No of close loop - Additional condition of equilibrium (members-1).

Dse=3+1+1-3=1.
Dsi = 3 * 2-(m-1)-(m-1) = 6-(2-1)-(2-1)=4 .

Hinge is placed in between 2member so (m-1) is (2-1).

Prenita said: (Mar 11, 2019)  
3*7 + 4-3 * 6-2 = 5.

Prenit said: (Mar 11, 2019)  
Thank you all for explaining.

Vikasgowda C J said: (Aug 2, 2020)  
Ds=Dse+Dsi.
Dse= no.Of reactions(r) - no.of equilibrium equn(s)
Dse= 4 - 3.
Dse= 1

Dsi= 3( no of closed-loop in a structure) -releases( when a hinge is present between members)

i.e, if the hinge is present between 2 members= m-1=2-1=1.
Dsi = 3C-1-1= 3(2)-2 = 6 - 2 = 4.
Ds = 1 + 4 = 5.

Mumtaz Ali said: (Nov 18, 2020)  
Ds = Dsi + Dse = 4 + 1= 5.

Post your comments here:

Name *:

Email   : (optional)

» Your comments will be displayed only after manual approval.